X^2-7x-4=0
(x-7/2)^2-(7/2)^2-4=0
(x-7/2)^2-(7)^2/(2)^2-4=0
(x-7/2)^2-49/4-4=0
(x-7/2)^2+(-49-4*4)/4=0
(x-7/2)^2+(-49-16)/4=0
(x-7/2)^2+(-65)/4=0
(x-7/2)^2-65/4=0
(x-7/2)^2-65/4+65/4=0+65/4
(x-7/2)^2=65/4
sqrt[ (x-7/2)^2 ]=+-sqrt(65/4)
x-7/2=+-sqrt(65)/sqrt(4)
x-7/2=+-sqrt(65)/2
x-7/2+7/2=+-sqrt(65)/2+7/2
x=7/2+-sqrt(65)/2
x=[7+-sqrt(65)]/2
x1=[7-sqrt(65)]/2
x2=[7+sqrt(65)]/2
Answer:
Judy hiked: 
Step-by-step explanation:
The first trail =
miles
The second trail = 1 1/2 times longer than the first
miles
Total trails then becomes:

Answer:
Step-by-step explanation:
- <em>Refer to attached diagram (not to scale).</em>
- <em>Given details are reflected.</em>
<u>First find the measure of angle Q</u>
- m∠Q = 36° + (180° - 125°) = 91°
a) <u>Use law of cosines to find x:</u>
- x = √(160² + 200² - 2160*200*cos 91°) = 258 km (rounded)
<u>Use the law of sines to find the missing angles:</u>
- 258 / sin 91 = 160 / sin R = 200 / sin P
- m∠R = arcsin (160 sin 91° / 258) = 38°
- m∠P = 180° - (91° + 38°) = 51°
b) <u>Bearing P from R:</u>
- 360° - (55° + 38°) = 267°
c) <u>Bearing R from P:</u>
<span>The Range Rule of Thumb says that the range is about four times the standard deviation. (i.e. two standard deviations to the left and two standard deviations to the right of the mean).
Given that the mean is 500 and the standard deviation is 50, then
The minimum and the maximum "usual" values are given by

Therefore, the minimun "usual" value is 400 while the maximum "usual" value is 600.
</span>
I am guessing your question is <span>A row of plaques covers 120 square feet of space along a wall. If the plaques are 3 feet tall, what length of the wall do they cover?
I know the answer to this question because i had to do this for a test before. and the answer is that it covers 140 ft of the wall</span>