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Leya [2.2K]
3 years ago
6

Write the polynomial in standard form. Then name the polynomial based on its degree and number of terms.

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

4x^3+x+7

Step-by-step explanation:

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7. Select True or False for each statement.
rewona [7]
A. True
B. False
C. False
D. False
E. True

B. Quadrant II contains ordered pairs of the form (negative number, positive number)
C. (-6,0) is located on the x-axis
D. The origin is not located on any of the quadrant. It’s in the center
8 0
3 years ago
TV−→− bisects ∠RTS. If the m∠RTV=(16x−6)° and m∠VTS=(13x+9)° , what is the value of x and the m∠RTV ?
natta225 [31]

Answer:

x = 5

RTV = 74

Step-by-step explanation:

Given

RTV=16x - 6

VTS=13x+9

Required

Determine the values of x and RTV

Since, TV is a bisector, then

RTS = RTV + VTS --- (1)

and

RTV = VTS -- (2)

Substitute values of RTV and VTS in (2)

16x - 6 = 13x + 9

Collect Like Terms

16x - 13x = 9 + 6

3x = 15

Solve for x

x = 5

Substitute 5 for x in RTV=16x - 6

RTV = 16 * 5 - 6

RTV = 80 - 6

RTV = 74

8 0
3 years ago
Can anyone help me in these questions
polet [3.4K]

Answer:

the answer should be 25 times 25=625, also 12 times 12= 144 625+144=769

Step-by-step explanation:

brainliest??????

8 0
2 years ago
Can you help me plsssss
garri49 [273]
I think it’s B sorry if I’m wrong
8 0
2 years ago
Read 2 more answers
Last digit (unit digit) of 2^2014
Drupady [299]

Answer:

4

Step-by-step explanation:

Let's find a pattern.

2^0=1

2^1=2

2^2=4

2^3=8

2^4=16

2^5=32

2^6=64

2^7=128

2^8=256

So starting after power of 0, the pattern begins at power=1. The pattern is 2,4,8,6 for the units digit. Since the pattern repeats in 4, then we shall divide the power in question by 4 seeking it's remainder.

Remainder=1 implies unit digit is 2 (see 2^1=2)

Remainder=2 implies unit digit is 4 (see 2^2=4)

Remainder=3 implies unit digit is 8 (see 2^3=8)

Remainder=0 implies unit digit is 6 (see 2^4=16)

2014/4 = 503 + 2/4

So remainder=2 implies unit digit is 4.

7 0
2 years ago
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