Step-by-step explanation:
2x + 100 = 90
x = -5
Angle A = 45 - 5 = 40.
Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
Answer:
Function B has a greater rate of change
Step-by-step explanation:
to find the rate of change or slope
Function A
(0,2) (3,5)
m =(y2-y1)/(x2-x1)
= (5-2)/(3-0)
= 3/3
m=1
Function B
m =(y2-y1)/(x2-x1)
= (9-6)/(6-4)
= 3/2
= 1.5
Function B has a greater rate of change
Answer:
th part of the field is covered in the second sprint.
Step-by-step explanation:
A football player is running the length of a 100 yard long football field.
Let player sprints x yards with the speed = 2 yards per second.
So time taken to cover x yards player will take time = 
seconds
Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = 
= 
seconds
Now total time taken by the player can be represented by the equation
Now we can solve this equation for the value of x.
x + 100 = 40×4
x + 100 = 160
x = 160 - 100 = 60 yards
And length of the second part will be = 100 - 60 = 40 yards
Now the fraction of the field covered by the player in second sprint will be
= 
= or 40%
Therefore, th part of the field was covered in second sprint.
Idk but it can't be 10 or 9.7 bc a triangle's hypotenuse is always longer than its legs
