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Natali5045456 [20]
3 years ago
5

A window shaped like a parallelogram has a has a area of 18 1/3 square feet. The height of the window is 3 1/3 feet. How long is

the base of the window?
Mathematics
1 answer:
RideAnS [48]3 years ago
4 0

Answer:

5.5 feet

Step-by-step explanation:

This is because 3 1/3 times 5.5 is 18 1/3

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14. Shaun has a bag with 12 yellow tiles and
ollegr [7]
3 should be added to the tiles
5 0
3 years ago
Solve x(x-1) (X-5) <=O​
lara [203]

Answer:

x <= 0 or  1 = < x <= 5.

Step-by-step explanation:

First we find the critical points:

x(x - 1)(x - 5) = 0

gives x = 0, x = 1 and x = 5.

Construct a Table of values:

               <u>  x < 0 </u>  <u>x = 0 </u> 0<u>< x < 1</u>  <u>1 =< x <= 5</u>     <u>x = 5</u>

x                  <0        0          >0             <0           0

x - 1             <0       -1           >0              <0           0

x - 5            < 0       0          > 0             <0           0

x(x-1)(x-5)    < 0      0          >0              <0          0 

So the answers are x =< 0 or  1 =< x <= 5.

8 0
3 years ago
An ice cream cone has a diameter of 12.8 cm and a slant height of 9 cm. Find the lateral surface area of the cone. Use 3.14 for
Makovka662 [10]

Answer:

about 181 or 180.96

Step-by-step explanation:

π·6.4·6.332+6.42≈180.9555

7 0
2 years ago
Find the measure of XCY. PLEASE HELP ME AND SHOW WORK
Dovator [93]

Answer:

Measure of angle XCY is 60°.

Step-by-step explanation:

"Measure of all inscribed angles by the same arc in one segment of the circle are equal"

Using this property in the given circle,

m∠XWY = m∠XCY

60x = 61x - 1

61x - 60x = 1

x = 1

By substituting the value of 'x' in the measure of ∠XCY,

m∠XCY = 61x - 1

             = 61(1) - 1

             = 61 - 1

             = 60°

Therefore, measure of angle XCY is 60°.

4 0
2 years ago
Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0
cestrela7 [59]
When n=0, you have

4^0=1\equiv3(0)+1=1\mod9

Now assume this is true for n=k, i.e.

4^k\equiv3k+1\mod9

and under this hypothesis show that it's also true for n=k+1. You have

4^k\equiv3k+1\mod9
4\equiv4\mod9
\implies 4\times4^k\equiv4(3k+1)\mod9
\implies 4^{k+1}\equiv12k+4\mod9

In other words, there exists M such that

4^{k+1}=9M+12k+4

Rewriting, you have

4^{k+1}=9M+9k+3k+4
4^{k+1}=9(M+k)+3k+3+1
4^{k+1}=9(M+k)+3(k+1)+1

and this is equivalent to 3(k+1)+1 modulo 9, as desired.

3 0
3 years ago
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