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Luba_88 [7]
3 years ago
15

A composition of transformations maps ∆KLM to ∆K"L"M". The first transformation for this composition is _______, and the second

transformation is a translation down and to the right
A. a 90° rotation about point L
B. a 270° rotation about point L
C. a 90° rotation about point P
D. a 270° rotation about point P​

Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0

Answer: a 270 rotation about point p

Step-by-step explanation:

Nadusha1986 [10]3 years ago
3 0

Answer:

Option D.

Step-by-step explanation:

Since MK and M'K' are at 90° after transformation which means MK is rotated either 90° clockwise about P or 270° counterclockwise about P.

So the composition of transformations which maps ΔKLM to ΔK"L"M", the first transformation for this composition is rotation of 270° counterclockwise about the point P.

And the second transformation is a translation down and to the right.

"Option D. a 270° rotation about point P" is the answer.

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Plz hurry!!!! thank you!!!!
RoseWind [281]

Answer:

m\angle KLM=53.13^o

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle KOM

In the triangle KOM

we have

KO=MO=r=5\ units

KM=8\ units

Applying the law of cosines

8^2=5^2+5^2-2(5)(5)cos(KOM)

64=50-50cos(KOM)

50cos(KOM)=50-64

50cos(KOM)=-14

cos(KOM)=-14/50

m\angle KOM=cos^{-1}(-14/50)

m\angle KOM=106.26^o

step 2

Find the measure of the arc KM

we know that

arc\ KM=m\angle KOM ----> by central angle

we have

m\angle KOM=106.26^o

so

arc\ KM=106.26^o

step 3

Find the measure of angle KLM

we know that

The inscribed angle is half that of the arc comprising  

m\angle KLM=\frac{1}{2}[arc\ KM]

we have

arc\ KM=106.26^o

substitute

m\angle KLM=\frac{1}{2}[106.26^o]

m\angle KLM=53.13^o

7 0
3 years ago
What are the values of a and b?
ivann1987 [24]

Answer:

<h2>a = 400/21, b = 580/21</h2>

Step-by-step explanation:

Small triangles are similar. Therefore, the sides are proportional

\dfrac{a}{20}=\dfrac{20}{21}               <em>cross multiply</em>

21a=(20)(20)       <em>divide both sides by 21</em>

a=\dfrac{400}{21}

For b, we can use the Pythagorean theorem:

b^2=\left(\dfrac{400}{21}\right)^2+20^2\\\\b^2=\dfrac{160000}{441}+400\\\\b^2=\dfrac{160000}{441}+\dfrac{176400}{441}\\\\b^2=\dfrac{336400}{441}\to b=\sqrt{\dfrac{336400}{441}}\\\\b=\dfrac{\sqrt{336400}}{\sqrt{441}}\\\\b=\dfrac{580}{21}

3 0
3 years ago
The straight line P has the equation y= 2x-5
Sunny_sXe [5.5K]

Answer:

y=−x/2+2.

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=2x−5.

The slope of the perpendicular line is negative inverse: m=−12.

So, the equation of the perpendicular line is y=−x/2+a.

To find a, we use the fact that the line should pass through the given point: 3=(−12)⋅(−2)+a.

Thus, a=2.

Therefore, the equation of the line is y=−x/2+2.

4 0
3 years ago
Explain how you write products when there are not enough digits in the product to place a decimal point
Anni [7]
If you there isn't enough digits to place, just add zeroes to product to make it a full product or don't even use a decimal point at all.
6 0
2 years ago
Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.
umka21 [38]
Complex zeroes always occurs as conjugates.
For z = a + b i conjugate is: a - b i
Another zero is : 2 + 3 i.
Verification:
2 + 3 i + 3 - 3 i = - b/a
- b = 4,  a = 1
( 2 + 3 i ) ( 2 - 3 i ) = c / a
4 - 9 i² = c / a
4 + 9 = c / a
c = 13
( x^4 - 4 x³ + 14 x² - 4 x + 13 ) : ( x² - 4 x + 13 ) = x² + 1
x² + 1 = 0
x² = -1,  x = i,  x = -i
The zeroes are: - i , i , 2 + 3 i, 2 - 3 i.
Answer: 
One another zero of f ( x ) is 2 + 3 i.
7 0
3 years ago
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