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3 years ago

Draw pictures to show a third of a whole and a fourth of a whole

Mathematics

2 answers:

enot [183]3 years ago

8 0

I attached two photos below. The first circle that is divided into 4 sections shows 1/4 of the circle shaded in green. The second circle is divided into 3 sections which shows 1/3 of the circle colored in with black lines.

kkurt [141]3 years ago

6 0

2/3 is 2 parts of three being used. 1/4is 1 peice of four say you have a tea set it has 4 peices and you lost three of the pieces now you have 1/4 of the tea set left

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I know the unit rate but don’t know the label.

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Miles per minute or miles per hour depending on how you did it.

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3 years ago

What is the equation of the line that passes through the point (-5, 7)<br> and has a slope of –1/5?

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3 years ago

How to solve x/3 + 4 = -2

r-ruslan [8.4K]

Answer:

x=−18

Step-by-step explanation:

Let's solve your equation step-by-step.

+4=−2

Step 1: Simplify both sides of the equation.

x+4=−2

Step 2: Subtract 4 from both sides.

x+4−4=−2−4

x=−6

Step 3: Multiply both sides by 3.

3*(

x)=(3)*(−6)

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3 years ago

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. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(U |D ) = 0.198$

$P(O\ n \ B) = 0.188$

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

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3 years ago

Damon and Eddie each had an equal amount of money. Each day Damon spent $18 and Eddie spent $24. When Eddie used up all his mone

Zina [86]

D = $18
E = $24
x - $18 = 120
x = $138

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3 years ago

Read 2 more answers