Order doesn't mater so use combinations:
6C3 = 6!/ (3! (6-3)! ) = 6! /(3!*3!) = 6*5*4*3! / (3! 3!) = 6*5*4/3*2*1) = 20
Answer:
a. f(0) = 4
b. f(6) = 8
Step-by-step explanation:
This is a piecewise function, so the actual equation is on the left, and the inequalities are on the right.
If x = 0, this would fall under the first part of the function because x < 5 is the requirement for the first part. Then, evaluating it: f(0) = 0 + 4 = 4.
If x = 6, this would fall under the second part of the function because 5
x < 7 is the requirement. 6 falls under this category, so that means the second part of the function is used. Because it is a constant, 8, this evaluates to f(6) = 8.
The appropriate choice is z = 1.41.
The empirical rule tells you 68% of the distribution is within 1 standard deviation, so p(z > 1) ≈ 0.17. This means the z value is more than 1 for the probability to drop to 0.08. The only choice that is greater than 1 is 1.41. (The number is actually about 1.40507.)
The train has 12 carriages
Step-by-step explanation:
The total no. of seats =876
No. of seats per carriage =73
It is given that each carriage has equal seats
So,
Let the total no. of carriages be x
According to the given information,


x = 12
Hence the number of carriages is 12
To know more about numbers,
brainly.com/question/11793415
Answer:
the question is missing, please try again.
Step-by-step explanation: