Answer:
a)
<u>The discount id 40%, so the function is:</u>
b)
- p = 100 ⇒ d = 40
- p = 200 ⇒ d = 80
- p = 300 ⇒ d = 120
- p = 400 ⇒ d = 160
- p = 500 ⇒ d = 200
<em>The graph is attached</em>
c)
- p = $85 ⇒ d = 0.4*$85 = $34
<u>Sale price is:</u>
- CP = p - d = $85 - $34 = $51
Answer:
3.73 ( The three is infinite)
Step-by-step explanation:
Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8
b) P(7 of the players number are drrawn)=3.33×10^-c) P(at least 6 of the players number were drawn)=1.84×10^-4
Step-by-step explanation:
Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40
a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8
There are one in hundred million chances that the draw numbers are precisely the chosen ones.
b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)
8×32
P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.
There are approximately 300,000 chances that 7 of the players numbers are chosen
c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.
P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]
P(at least 6 players numbers are drawn) = 1.84×10^-4.
There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.
Answer:
Step-by-step explanation:
a. Profit, p, earned from selling x hats when hat will be sold for $12 each:
p = 12x
b. To recover the cost of making the 200 hats which is $1500, profit, p >= cost:
p = 12x >= 1500
x >= 1500/12 = 12.5
So the minimum number of hats that must be sold = 13
c. New hat price = $15 so p = 15x
p = 15x >= 1500
x >= 1500/15 = 10
So the new minimum = 10 which is 3 fewer.
Change the mixed fractions to an improper fraction.
4 5/7 = 32/7
1 6/7 = 13/7
Now you can easily subtract since both fractions have common denominators
32/7 - 13/7
(Think: 32 - 13 = 19)
Change the improper fraction to a mixed fraction
19/7 = 2 5/7
Answer: 2 5/7
Hope I helped =)
