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3 years ago

I really need help with this last problem

Mathematics

2 answers:

koban [17]3 years ago

4 0

Answer:

a. p=12*x

b. x=13

c. x=10, 3 fewer

Step-by-step explanation:

a. hat is 12 ea. so profit, p, from selling x hats = 12*x

b. cost=1500

profit > cost to recover

12*x >= 1500

x >= 12.5 but no. of hats sold is integer

x=13

c. new price=15

15*x >= 1500

x >=10

x=10, 3 fewer hats

gogolik [260]3 years ago

3 0

Answer:

Step-by-step explanation:

a. Profit, p, earned from selling x hats when hat will be sold for $12 each:

p = 12x

b. To recover the cost of making the 200 hats which is $1500, profit, p >= cost:

p = 12x >= 1500

x >= 1500/12 = 12.5

So the minimum number of hats that must be sold = 13

c. New hat price = $15 so p = 15x

p = 15x >= 1500

x >= 1500/15 = 10

So the new minimum = 10 which is 3 fewer.

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Solve 5x^2 − 3x + 17 = 9.

Vedmedyk [2.9K]

Answer:

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

⇒ 5x² − 3x + 17 - 9 = 0

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = $\frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}$

x = $\frac{3\pm\sqrt{9-160}}{10}$

x = $\frac{3+\sqrt{-151}}{10}$ and x = $\frac{3-\sqrt{-151}}{10}$

x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

here i = √(-1)

Hence,

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

7 0

2 years ago

Each lap around a park is 0.58 miles. Jessica walked 3.25 laps around the park. How many miles did Jessica walk around the park?

xz_007 [3.2K]

0.58x3.25=1.885
c.)1.885 miles

6 0

2 years ago

f of x equals 4 x over quantity x squared minus 16. Show all work to identify the asymptotes and zero of the function.

yuradex [85]

Given:

The function is

$f(x)=\dfrac{4x}{x^2-16}$

To find:

The asymptotes and zero of the function.

Solution:

We have,

$f(x)=\dfrac{4x}{x^2-16}$

For zeroes, f(x)=0.

$\dfrac{4x}{x^2-16}=0$

$4x=0$

$x=0$

Therefore, zero of the function is 0.

For vertical asymptote equate the denominator of the function equal to 0.

$x^2-16=0$

$x^2=16$

Taking square root on both sides, we get

$x=\pm \sqrt{16}$

$x=\pm 4$

So, vertical asymptotes are x=-4 and x=4.

Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.

8 0

3 years ago

21 is 30% of what number?

WARRIOR [948]

Answer:

21 is 30% of 70

Explanation:

We know that 100% is the original number.

Equation:

(21/30)*100

21/3 * 10

7 * 10

70 ....this is the answer, original number.

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2 years ago

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10 + 2-x\3 = 7 \ = divided by TIA!

Lemur [1.5K]

Your answer to this problem is 15

10 + 2 - 15 / 3 = 7

Hope it helped :)

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3 years ago