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mr_godi [17]
3 years ago
13

The number of pieces of popcorn in a large movie theatre popcorn bucket is normally distributed, with a mean of 1515 and a stand

ard deviation of 15. Approximately what percentage of buckets contain between 1470 and 1560 pieces of popcorn?
Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer: 99.7%, Im pretty confident about that. Im taking the test right now.

Step-by-step explanation:

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Neko [114]
That is not correct.  I will help you.  Begin by subtracting the 9x from both sides, like this:  9x - 9x + 2y = 6 - 9x.  That simplifies to 2y = -9x + 6.  Now divide both sides by 2 to get y all alone, like this:  \frac{2y}{2}=- \frac{9}{2}x+ \frac{6}{2}.  That reduces down to y=- \frac{9}{2}x+3.  That is slope-intercept form.  y = mx + b.
7 0
3 years ago
Solve 73 make sure to also define the limits in the parts a and b
Aleks04 [339]

73.

f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}

a)

\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3

b)

Since we can't divide by zero, we need to find when:

x^4-2x^2+144=0

But before, we can factor the numerator and the denominator:

\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}

Now, we can conclude that the vertical asymptotes are located at:

\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}

so, for x = -3:

\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty

For x = 4:

\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty

4 0
1 year ago
What is the highest common factor of 33 and 93
antoniya [11.8K]
The highest is 3 does this help u?
4 0
3 years ago
Lloyd is making goblins and elves on a video game. It takes 6 rounds to make a goblin and 8 rounds to make an elf. If he complet
marusya05 [52]

Answer:

24 rounds

Step-by-step explanation:

This question has to do with a factor of numbers which we refer to as:

Lowest common multiple.

Lowest common multiple can be defined as the Lowest multiple that is common to the multiple of two numbers.

We are told in the question that:

Lloyd is making goblins and elves on a video game. It takes 6 rounds to make a goblin and 8 rounds to make an elf.

We find the multiples of 6 and 8

6 = 1, 6, 12, 18, 24, 48, 54, 60, 66, 72 e.tc.

8 = 1, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, e.t.c

The Lowest Common Multiple: This is the least or lowest multiple that is common to both 6 and 8

= 24.

Therefore, it will take 24 rounds for Lloyd to complete another goblin and elf at the same time

4 0
3 years ago
A researcher is interested in estimating the mean weight of a semi tracker truck to determine the potential load capacity. She t
uranmaximum [27]

Answer:

The degrees of freedom associated with this problem are 16.

Step-by-step explanation:

The degrees of freedom associated with a problem, independent of the confidence level, is the sample size subtracted by 1.

In this problem, we have that:

She takes a random sample of 17 trucks, so the sample size is 17.

This means that the degrees of freedom associated with this problem are 16.

4 0
3 years ago
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