Question

A coordinate plane with a line drawn passing through the points (0, 3) and (3, 2).

Answer 1

Answer:

None of the equations given is the equation of the function. The correct equation is: $y=-\frac{x}{3}+3$

Step-by-step explanation:

First we must find the slope of the line that passes through these points.

The slope between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given by:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

where $m$ is the slope

In this case since we have the points: $(0, 3)$ and $(3, 2).$

$x_{1}=0\\y_{1}=3\\x_{2}=3\\y_{2}=2$

and the slope will be:

$m=\frac{2-3}{3-0}=\frac{-1}{3}$

and now we have the slope we use the slope-point equation:

$y=m(x-x_{1})+y_{1}$

$y=-\frac{1}{3}(x-0)+3\\ y=-\frac{x}{3}+3$

Answer 2

Answer:

y-y1=m(x-x1)

y-2=-1/3 x + 1

y=-1/3 x +1+2

y=-1/3x+3