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Savatey [412]
1 year ago
11

14. If the domain of f(x)= x2 +1 is limited to {0,1,2,3), what is the maximum value of the range?

Mathematics
1 answer:
fiasKO [112]1 year ago
7 0

the domain of f(x)= x2 +1 is limited to {0,1,2,3)

the maximum value will be at the maximum value of x which is at x = 3

So, the maximum value of the range will be = 3^2 + 1 = 9 + 1 = 10

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Answer:

The points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

Step-by-step explanation:

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y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

So, the equation of the line passing through two points (0,5) and ( 2, 8 ) is

y-5=\frac{8-5}{2-0}(x-0)

\Rightarrow y=1.5x+5\cdots(i)

For the point (4,11), pout x=4 in equation (i), we have

y=1.5\times4 +5=11, which is given y coordinate, hence this point (4,11) lies on the line.

For the point (5,10), pout x=5 in equation (i), we have

y=1.5\times5 +5=12.5, which is not the given y coordinate, hence the point (5,10) doesn't lie on the line.

For the point (6,14), pout x=6 in equation (i), we have

y=1.5\times6 +5=14, which is the given y coordinate, hence the point (6,14)  lies on the line.

For the point (30,50), pout x=30 in equation (i), we have

y=1.5\times30 +5=50, which is the given y coordinate, hence the point (30,50) lies on the line.

For the point (40,60), pout x=40 in equation (i), we have

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Hence, the points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

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3 years ago
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