All categories

2 years ago

What do you say about the proposition "4 divides n" compared to the proposition "2 divides n"?

Mathematics

1 answer:

likoan [24]2 years ago

7 0

Answer:

добре звучи добре

Step-by-step explanation:

You might be interested in

Margaret goes to the county fair with $35. Rides cost $3 each. Write an equation that gives the amount of money m that Margaret

Oksi-84 [34.3K]

Answer:

11.

Step-by-step explanation:

I got the answer of 11, as I:

-First, I worked out how many rides Margaret would be able to go on, so I did $35 -/- $3, which was a decimal, but the most amount of times would be 11 rides that she could go on, therefore, that's the amount of rides she would take, and have $2 left over.

Hope this helps!

--Emilie Xx

3 0

3 years ago

Read 2 more answers

Find the greatest common factor of 9 and 14

Ratling [72]

The biggest common factor number is the GCF number. So the greatest common factor 9 and 14 is 1.

5 0

3 years ago

Read 2 more answers

- Two cars leave the same parking lot, with one heading north and the other heading east. After several minutes, the northbound

PIT_PIT [208]

Answer:

Step-by-step explanation

Use Pythagoras theorem. The distance between the cars, 8km, is the hypotenuse of a right angled triangle, one leg of which is 6km and the other of which is, say, x km

x = sqrt(8^2 - 6^2) km.

You can crunch the numbers.

4 0

2 years ago

3h-k=10<br>h-k=2<br>can u guys please help me

katen-ka-za [31]

Hi, hope this helps :)

8 0

3 years ago

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

3 years ago

Read 2 more answers