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vlabodo [156]
3 years ago
14

1 Diego cut 7 smaller boards of equal length from a board that is 9 1/3 feet long. How long is each of the 7 smaller boards?​

Mathematics
2 answers:
ivanzaharov [21]3 years ago
5 0

Answer:

4/3

Step-by-step explanation:

because if you caculate right and do the answer correctly it is D. thanks can i get brainlest.

Sophie [7]3 years ago
4 0

Answer:

4\3

Step-by-step explanation:

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19. A sample of 50 retirees is drawn at random from a normal population whose mean age and standard deviation are 75 and 6 years
Juliette [100K]

Answer:

a) Approximately normal.

b) The mean is 75 years and the standard deviation is 0.8485 years.

c) 0.9909 = 99.09% probability that the mean age exceeds 73 years

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Sample of 50 retirees

This means that n = 50

Mean age and standard deviation are 75 and 6 years

This means that \mu = 75, \sigma = 6

a. Describe the shape of the sampling distribution of the sample mean in this case

By the Central Limit Theorem, approximately normal.

b. Find the mean and standard error of the sampling distribution of the sample mean.

By the Central Limit Theorem, the mean is 75 and the standard error is s = \frac{6}{\sqrt{50}} = 0.8485

c. What is the probability that the mean age exceeds 73 years?

This is 1 subtracted by the pvalue of Z when X = 73.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{73 - 75}{0.8485}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

1 - 0.0091 = 0.9909

0.9909 = 99.09% probability that the mean age exceeds 73 years

5 0
2 years ago
Alexis has to ribbons what is 40 cmeters long in the other 170 long she wants to cut each ribbon equal spaces with no ribbon lef
lana [24]
Ndlsallasisizjzjzkslaalslwlekkdjdjxbsb goodluck got you!!
7 0
2 years ago
write the equation of a line in slope intercept form that passes through (2 -2) and is parallel to 2x+4y=8
Ne4ueva [31]

Answer:

y= -1/2x-1

Step-by-step explanation:

1) put the equation in y-intercept form to find the slope of the original line 2x+4y=8

y=8/4-2x/4

y=2-1/2x

slope of second line will be -1/2

2) put point into the point-slope form (2,-2)

y-(-2)= -1/2(x-2)  now simplify

y+2= -1/2x+2/2

y+2 = -1/2x + 1

y+2-2=-1/2x + 1 -2 ====>>>>  y= -1/2x-1

8 0
2 years ago
Can someone pls help
Cloud [144]

Answer:

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
2sin^(-2490)+tan 1410
givi [52]
2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6

Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6    (≈-0.07735...)
7 0
3 years ago
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