Answer: £122.4
Step-by-step explanation:
Given
The rate of interest is 4%
The principal invested is £1500
the time period is 2 years
Compound interest is given by

put values
![C.I.=1500(1+0.04)^2-1500\\C.I.=1500[1.04^2-1]\\C.I.=1500[1.0816-1]\\C.I.=1500\times 0.0816\\C.I.=122.4](https://tex.z-dn.net/?f=C.I.%3D1500%281%2B0.04%29%5E2-1500%5C%5CC.I.%3D1500%5B1.04%5E2-1%5D%5C%5CC.I.%3D1500%5B1.0816-1%5D%5C%5CC.I.%3D1500%5Ctimes%200.0816%5C%5CC.I.%3D122.4)
Therefore, interest earned is £122.4
Answer:
8/7
Step-by-step explanation:
(2,-5) (9,3)
3-(-5)=8 because you apply your keep change change
9-2= 7
so 8/7

To find the gradient of the tangent, we must first differentiate the function.

The gradient at x = 0 is given by evaluating f'(0).

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
It should take 2.2 hours, since 5.5 / 2.5 = 2.2.