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3 years ago

6

PLEASE EXPALIN :))))) ( THERES A PIC)

1 answer:

Bond [772]3 years ago

3 0

Altitudes make right angles so it is C

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In a grocery store a $21 case of toilet paper is labeled, "Get a 20% discount." What is the discount? What is the sale price of

arsen [322]

Hi There!

Step-by-step explanation and Answer:

21 * 0.2 = $4.2 (Discount)

21 - 4.2 = $16.8 (Sale Price)

Hope This Helps :)

5 0

4 years ago

Read 2 more answers

Whats the answers to this question?

AnnyKZ [126]

Answer:

1) e = 6

2) w = 10

3) s = 27

4) t = 4

Step-by-step explanation:

Cross multiplication

3 0

3 years ago

Selecting an SUV with a blue exterior

frozen [14]

The answer is straightforward, by the "rule of product":

There are

3×8×2=48

3×8×2=48

different combinations (distinct possible cars) that can be created.

There 33 choices for body style; 88 choices for exterior colors, and 22 choices of interior color schemes:

Since each of these choices are independent (the choice of body style doesn't depend on exterior or interior color, e.g.) we multiply the number of choices for each quality to obtain: 3×8×2=483×8×2=48 distinct ways to create a car

6 0

2 years ago

What is the tangent to the circle

Leni [432]

Answer:

PQ

Step-by-step explanation:

TANGENT ALWAYS TOUCH TO THE CIRCUMFERENCE OF CIRCLE

7 0

4 years ago

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

3 years ago