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3 years ago

Someone please me thank you

Mathematics

1 answer:

RSB [31]3 years ago

7 0

Answer:

Graph dots in the points of the following:

(-4,10)

(-3,8)

(-2,6)

(-1,4)

(0,2)

(1,0)

(2,-2)

(3,-4)

(4,-6)

(5,-8)

(6,-10)

Connect these dots to make a line.

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Which is a solution to -5x 3x>22

erastova [34]

-5x + 3x > 22
-2x > 22
x < 22/-2 (greater than sign changes to less than sign when you divide with negative number)
x < -11

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3 years ago

HELP I DONT UNDERSTAND PLS HELPP :(

Nat2105 [25]

Answer:

Step-by-step explanation:

The table uses the domain -0.2 twice, but got different ranges both times, therefore meaning that this is not a function.

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3 years ago

Determine whether each set of numbers can be measure of the sides of a RIGHT triangle. Justify your answer.

Papessa [141]

Answer:

The side lengths cannot belong to a right triangle.

Step-by-step explanation:

This is a simple case of Pythagorean proof. If this triangle was a right triangle, 20^2 + 21^2 = 28^2. However, this is not the case. 20^2 + 21^2 = 841, which square root is 29.

If you forgot, the Pythagoren Theorem is: a^2 + b^2 = c^2.

Hope this helps!

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3 years ago

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Alja [10]

Answer:

the answer is d

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Find the area of each shaded region. give your answer as a completely simplified exact value in terms of pi. (no approximates)

frez [133]

Answer:

52 $\pi$

Step-by-step explanation:

We see that the radius of the big circle is 8m, and we see that the it is also the diameter of the second smallest circle. We also see that this diameter is split into two equal parts, and since the entire length is 8, each part will be 4. So what we need to do is find the area of each circle.

First we can start by finding the area of the smallest circle. The radius of this circle will be 4/2, 2. So the area of this circle will be $\pi$ $r^{2}$ , and in this case 4 $\pi$ .

Then we need to find the area of the bigger shaded portion, which will be the area of the big circle, minus the area of the smaller white circle.

First, lets find the are of the big circle, which again, will be $\pi$ $r^{2}$ . This time, we plug in a radius of 8, and we get 64 $\pi$ .

Next we find the area of the smaller white circle, again $\pi$ $r^{2}$ . We use a radius of 4 this time, giving us an area of 16 $\pi$ .

Now we subtract the two values we found previously to find the area of the just the bigger shaded portion. That value will be 64 $\pi$ -16 $\pi$ , which is 48 $\pi$

We then take 48 $\pi$ , and we add the small shaded portion, which had an area of 4 $\pi$ , and we add them, giving us a total of 52 $\pi$ .

Hope this helped.

4 0

3 years ago