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ivolga24 [154]
3 years ago
11

Someone please me thank you

Mathematics
1 answer:
RSB [31]3 years ago
7 0

Answer:

Graph dots in the points of the following:

(-4,10)

(-3,8)

(-2,6)

(-1,4)

(0,2)

(1,0)

(2,-2)

(3,-4)

(4,-6)

(5,-8)

(6,-10)

Connect these dots to make a line.

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Approximate the value of √110 to the neatest hundtedth.
alexandr1967 [171]
10.49 It was really 10.4880884817 but 8 rounds it up to 10.49
5 0
3 years ago
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Round 2.44 to the nearest whole number
Gala2k [10]
The answer that you are looking for is 2
6 0
3 years ago
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A study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school
nekit [7.7K]

Answer:

We conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

Step-by-step explanation:

We are given that a study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois.

Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids.

Let p_1 = <u><em>proportion of Illinois high school freshmen who have used anabolic steroids.</em></u>

p_2 = <u><em>proportion of Illinois high school seniors who have used anabolic steroids.</em></u>

SO, Null Hypothesis, H_0 : p_1=p_2      {means that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

Alternate Hypothesis, H_A : p_1\neq p_2      {means that there is a significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

The test statistics that would be used here <u>Two-sample z test for</u> <u>proportions</u>;

                        T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of high school freshmen who have used anabolic steroids = \frac{34}{1679} = 0.0203

\hat p_2 = sample proportion of high school seniors who have used anabolic steroids = \frac{24}{1366} = 0.0176

n_1 = sample of high school freshmen = 1679

n_2 = sample of high school seniors = 1366

So, <u><em>the test statistics</em></u>  =  \frac{(0.0203-0.0176)-(0)}{\sqrt{\frac{0.0203(1-0.0203)}{1679}+\frac{0.0176(1-0.0176)}{1366} } }

                                     =  0.545

The value of z test statistics is 0.545.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

3 0
3 years ago
A remote-control airplane is descending at a rate of
Aloiza [94]

Answer:

83 m

Step-by-step explanation:

23.6 x 3.5 = 82.6 ≈ 83 m

4 0
2 years ago
The gcf of two numbers is 170. neither number is divisible by the other. what is the smallest these two numbers could be? (prime
ivanzaharov [21]

Answer:

340

Step-by-step explanation:

Given: GCF of two numbers is 170. neither number is divisible by the other.

To Find: smallest of these two number.

Solution:

As GCF of two numbers is 170, both number are divisible by 170.

Prime factor of 170 =2\times5\times17

multiples of 170 are 1\times2\times5\times17=170

                                           2\times2\times5\times17=340

                                           3\times2\times5\times17=510

GCF of all three multiples is 170,

Here 340 and 510 are the two multiples whose GCF is 170 and neither is divisible by other

Hence the smallest of two is 340, the answer is 340

6 0
3 years ago
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