A 5.0-gram sample of zinc and a 50.-milliliter sample of hydrochloric acid are used in a chemical reaction. Which combination of
2 answers:
Answer:
(4) zinc powder and 3.0 M HCl(aq)
Explanation:
First consider the equation of reaction:
1 mole of Zinc requires 2 moles of HCl for reaction.
mole of zinc = mass/molar mass = 5.0/65.38 = 0.0765 mole
0.0765 mole of zinc will require: 0.0765 x 2 = 0.1530 mole HCl
Mole of 1.0 M HCl = Molarity x volume = 1 x 0.05 = 0.05 mole
Mole of 3.0 M HCl = 3 x 0.05 = 0.15
Hence, the 3.0 M HCl is what will give the required number of mole.
<em>Zinc in powder form will react faster compared to in strip because the former has higher surface area for reaction.</em>
Therefore, zinc powder and 3.0 M HCl will give the fastest reaction rate.
<em>The correct option is option 4.</em>
You might be interested in
Answer: 41.5 mL
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
Given : 59.4 g of in 100 g of solution
moles of
Volume of solution =
Now put all the given values in the formula of molality, we get
To calculate the volume of acid, we use the equation given by neutralisation reaction:
where,
are the molarity and volume of stock acid which is
are the molarity and volume of dilute acid which is
We are given:
Putting values in above equation, we get:
Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid