Answer:
22.77 g.
he limiting reactant is O₂, and the excess reactant is Mg.
Explanation:
- From the balanced reaction:
<em>Mg + 1/2O₂ → MgO,</em>
1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.
- We need to calculate the no. of moles of (16.3 g) of Mg and (4.52 g) of oxygen:
no. of moles of Mg = mass/molar mass = (16.3 g)/(24.3 g/mol) = 0.6708 mol.
no. of moles of O₂ = mass/molar mass = (4.52 g)/(16.0 g/mol) = 0.2825 mol.
So. 0.565 mol of Mg reacts completely with (0.2825 mol) of O₂.
<em>∴ The limiting reactant is O₂, and the excess reactant is Mg (0.6708 - 0.565 = 0.1058 mol).</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of Mg produce → 1.0 mol of MgO.
∴ 0.565 mol of Mg produce → <em>0.565 mol of MgO.</em>
<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.565 mol)(40.3 g/mol) = <em>22.77 g.</em>
Answer:
4.5 times 10 = 45
Explanation:
"Non-zero digits are always significant. Any zeros between two significant digits are significant. A final zero or trailing zeros in the decimal portion ONLY are significant."
Answer:
The correct option is;
2) Thermal energy increases by a factor of R
Explanation:
The equipartition energy theorem states that when molecules are in a state of thermal equilibrium, particles within the system posses equal average energy with each degree of freedom which can be known as energy due to a state of having a particular temperature or thermal energy given by the relation
= Kinetic energy of translation + Kinetic energy of rotation + Energy of vibration
For a mono-atomic gas,
= 3/2·n·R·T
For a diatomic gas,
= 5/2·n·R·T
For a solid element,
= 3·n·R·T
Therefore, as the temperature is doubled, the thermal energy increases by a factor of R.