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lord [1]
2 years ago
13

Precautions to take during electroplating

Chemistry
1 answer:
AnnZ [28]2 years ago
4 0

Answer:

Always be scared of electroplating. ...

Follow all electrical safety precautions. ...

Use all safety Precautions. ...

Use that Fume Hood. ...

It's a chemistry lab, set it up like one. ...

Always add acid to water. ...

Don't overheat your solutions! ...

Don't mix acid and cyanide solutions.

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Peer Review

Explanation:

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Does the law of inertia apply to both moving and non-moving objects
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A golf pro has 2100 J of kinetic energy and swings his driver which weighs .75 kg. What is the speed of his swing?
jeka57 [31]

Answer : The correct answer is 74.83 m/s .

The kinetic energy is energy possessed by any mass which is moving or have some speed . It is product of mass and velocity . It is expressed as :

KE = \frac{1}{2}  * m* v^2

Where KE = kinetic energy in J or kg\frac{m^2}{s^2} m = mass in Kg v = speed in m/s²

Unit of KE is Joules (J) .

Givne : KE = 2100 J mass = 0.75 kg v = ?

Plugging value in KE formula =>

2100 J = \frac{1}{2}  * 0.75 Kg * v^2

2100 J = 0.375 Kg * v^2

Dividing both side by 0.375 kg =>

\frac{2100 J}{0.375 Kg}  = \frac{0.375 Kg}{0.375 Kg } * v^2

v^2 = 5600 \frac{m^2}{s^2}

v= 74.83 \frac{m}{s}

8 0
3 years ago
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When 1.82 moles of HCL reacts with excess MnO2, how many moles of Cl2 form
s2008m [1.1K]

The balanced reaction is:<span>

MnO2(s) + 4HCl(aq) → Cl2(g) + MnCl2(aq) + 2H2O(l)

We are given the amount of hydrochloric acid to be used for the reaction. This will be the starting point for the calculations.

1.82 mol HCl ( 1 mol Cl2 / 4 mol HCl) = 0.46 mol Cl2

<span>Therefore, 0.46 mol of chlorine gas is produced for the reaction of hydrochloric acid and manganese oxide.</span></span>

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Write the balanced equation for the decomposition of hydrogen peroxide to form water and oxygen.
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Notice that the H2O2 has 2 H atoms, and so does H2. This means that both must have the same coefficients, and we can adjust the coefficient of O2. Since H2O2 has 2 O atoms, and H2O has 1, we multiply O2 by 1/2:
H2O2 --> H2O + (1/2)O2
This has an equivalent number of H and O atoms on either side, but we want the coefficients to be whole numbers, so we multiply everything by 2:
2H2O2 --> 2H2O + O2
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