Answer:
No hay resultados para ACFrOgDjZVP5d1mO2l6HAtPZQNnbFRq674g04E7uZadqJMPc4VbhdTIEDCWBeh3xfw9BrKkfHHEN4nxe9NVglsb9N8D49CjxvxHYw3L93m4wO6SY5SwKQYMk-2zzHtGzerun1Uh9k-mpxFw9D3I1.pdf
Explanation:
hablemos por g mail
Answer:
a. Clay
b. Sandy Loam
c. Sandy Clay
d. Loamy Sand
Explanation:
Based on the soil texture triangle, the soil texture for the following combination of sand, silt and clay are;
a. Sand 20 percent; Silt 20 percent;Clay 60 percent: ____ CLAY
b. Sand 60percent; Silt 30percent; Clay 10percent: ___ SANDY LOAM
c. Sand 50percent; Silt 10percent;Clay 40 percent: ____ SANDY CLAY
d. Sand 80 percent; Silt 15 percent; Clay 5percent:_____ LOAMY SAND
Answer:
3.50 molal
Explanation:
Molality → Moles of solute / kg of solvent.
Let's convert the solvent's mass from g to kg
16.2 g . 1kg / 1000 g = 0.0162 kg
Let's determine the moles from the solute
2.61 g . 1 mol / 46 g = 0.0567 moles
Molality → 0.0567 mol / 0.0162 kg = 3.50 m
There's a slight error in your equation. I think you were trying to present it like this:
2C8H18 + 25O2 -> 16CO2 + 18H2O
Mole Ratio
O2 : H20
25 : 18
? moles : 18 moles
(18/18)×25 : 18 moles
25 moles : 18 moles
Final answer would be 25 moles of O2. :)
If you have any doubts that you want to clarify with me, please ask me! :)
I will do my utmost best to help you.
