Answer:
1.) There are 16 juniors and 8 seniors in the Chess Club. If the club members decide to send 9 juniors to a tournament, how many different possibilities are there?
(16 over 9) = 16!/(9!*7!) = 11440
2.) How many different ways can 3 cards be drawn from a deck of 52 cards without replacement?
52*51*50 = 132600
3.) How many different ways can 3 cards be drawn from a deck of 52 cards with replacement?
52^3 = 140608
4.) A corporation has 5 officers to choose from which 3 are selected to comprise the board of directors. How many combinations are there?
(5 over 3) = 5!/(3! * 2!) = 10
5.) A combination lock has the numbers 1 to 40 on each of three consecutive tumblers. What is the probability of opening the lock in ten tries?
10/40^3 = 1/6400
The equation may also have one common root or no real roots. This gives the maximum number of points where the parabola<span> intersect as </span>2<span>. ... When that is the case, the twp </span>parabolas<span> intersect at 4 </span>distinct<span> points. The maximum number of points of intersection of </span>two distinct parabolas<span> is 4.</span>
Answer:
a = 2
Step-by-step explanation:
a = pt + q
p = -1
t = 4
q = 6
a = -1(4)+6
a = -4+6
a = 2
Answer:
y = -1x + 7
Step-by-step explanation:
y2 - y1 / x2 - x1
9 - 0 / -2 - 7
9 / -9
= -1
y = -1x + b
0 = -1(7) + b
0 = -7 + b
7 = b
2.25 dollars for each tube of paint. you just have to divide 18 and 8
