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masya89 [10]
2 years ago
13

Simplify. (5b2−3b+2)+(2b−4) A.5b2+5b+6 B.5b2−5b−6 C.5b2−b−2 D.6b4−2

Mathematics
2 answers:
mylen [45]2 years ago
7 0
The answer is: C

5b^2-b-2
xxTIMURxx [149]2 years ago
3 0

Answer:

5b2 - b -2

Step-by-step explanation:

The answer is (c)

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W(1,8),X(7,8),Y(4,5), and Z(1,2) select all methods you can use to prove WYZ is congruent to WYX
marin [14]
The distance between two points (x₁,y1),(x₂,y₂) is d
d= \sqrt{(x2-x1)^2 + (y2-y1)^2}

For the given problem we have
<span>W(1,8),X(7,8),Y(4,5), and Z(1,2)

The length of WY = </span>\sqrt{(4-1)^2 + (5-8)^2} = 3√2
The length of WX = \sqrt{(7-1)^2 + (8-8)^2} = 6
The length of WZ = \sqrt{(1-1)^2 + (2-8)^2} = 6
The length of XY = <span><span>\sqrt{(4-7)^2 + (5-8)^2} = 3√2
</span>The length of ZY = </span><span>\sqrt{(1-4)^2 + (2-5)^2} = 3√2

∴ WX = WZ  ⇒⇒⇒ proved
    XY = ZY   ⇒⇒⇒ proved
    WY = WY  ⇒⇒⇒ reflexive property

∴ Δ</span><span>WYZ is congruent to ΔWYX by SSS method</span>





5 0
3 years ago
the bottom of a 22-foot ladder must be placed 7 feet from a wall. to the nearest tenth of a foot, how far above the ground does
Kitty [74]
The ladder, the wall and the floor form together a triangle rectangle, where the ladder is the hypotenuse of the triangle and the floor and wall are the cathetus. We know from Pythagoreas theorem that the square of the hypotenuse is equal to the sum of the two cathetus squared added, so we can write an equation with the data we have:
hyp^2 = cath1^2 + cath2^2
<span>hyp^2 = wall^2 + floor^2
</span>so we have the hypotenuse value, the floor value and the unknown is the wall height:
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484 = wall^2 + 49
wall^2 = 484 - 49 = 435
wall = √435
wall = 20.9
therefore the ladder touches the wall 20.9 feet above the ground
5 0
3 years ago
A bag contains​ pennies, nickels,​ dimes, and quarters. There are 50 coins in all. Of the​ coins, 10​% are pennies and 36​% are
adell [148]
If my calculations are correct it’s $6.80
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