Answer:
2.5e-0.04x = 1.2 + 0.2x
Step-by-step explanation:
Given that:
Insect A:
Initial population, Po = 2.5 million
Rate of decline = 4%
Insect B:
Initial Population (Po) = 1.2 million
Yearly increase = 200,000 = (200,000/1,000,000) = 0.2
For insect A:
P(t) = Po(1 - r)^t = Po*e^-rt
Po*e^-rt = 2.5e^-0.04t ----(1)
For Insect B:
P(t) = Po + (yearly increase) * t
P(t) = 1.2 + 0.2t - - - - - (2)
Equating (1) and (2)
2.5e^-0.04t = 1.2 + 0.2t
Answer:
0.000003721m
Scientific Notation: 3.72*10^-6
Step-by-step explanation:
1nm is 1*10^-6nm
Based on that we find the answer above.
Answer:
(Kind of cheating but since you're timed I'm just gonna five you the answer:
3/11
Step-by-step explanation:
I got this by guessing a bit, I used what varibles I had and 0.27 & 3 and used them.
So 3/0.27 = 11.11 (Repeating) so then I rounded this to a whole number,
3/11 = 0.27 (Repeating)