The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Set measurements equal to each other.
7X + 20 = 8X + 8
-7X -7X
20 = X + 8
-8 -8
ANSWER: X=12
If so, start by factoring the numerator. Then cancel any common term in the numerator and denominator. If you end up with no denominator, then use the original denominator. Set it equal to zero and solve for x. That value of x will be the restriction.
(10/12) / (4/6)...when dividing with fractions, flip what u r dividing by, then multiply
10/12 * 6/4 = 10/8 which reduces to 5/4 or 1 1/4
Answer:
0. 33 por que los jamones sivieron a 15 pesos y mi mama se va asta otro lado para compralo