Question

What is the equation of the line that passes through the point (5,-2) and has a slope of 6/5

Answer 1

Answer:

y = $\frac{6x}{5}$ - 8

Step-by-step explanation:

given slope m = $\frac{6}{5}$

point (5, -2) for (x1, y1)

equation for point slope form

y - y1 = m(x- x1)

y - (-2) = $\frac{6}{5}$ (x -5)

y + 2 = $\frac{6}{5}$x - 6, simplify

y = $\frac{6x}{5}$ - 8,

further you can multiply by 5 to get rid of fraction

5y = 6x - 40