Given :
On a coordinate plane,a curved line with 3 arcs, lab led f of x, crosses the x-axis at (negative 2,0), (negative 1,0), (1,0), and (3,0) and the y axis at (0, negative 6).
To find:
f when x = 0. i.e. f (0).
Solution:
since the graph has 3 arcs and 4 solutions, it can be visualized as the follows:
Between each solution, the function has to increase and decrease giving arcs in between.
1. One of the arcs is between (negative 2,0) and negative (1,0)
2. Second arc is between (negative 1,0) and (1,0)
-this arc cuts the y axis, since x= 0 lies between x= -1 & x=1-
3. Third arc is between (1,0) and (3,0)
Therefore only the 2nd arc cuts the y axis
It’s given that the curve cuts the y axis at (0, -6)
That is when x= 0, f(0) =-6
Therefore the value of f (0) is -6 only.
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ANSWER

EXPLANATION
Recall that,

But we were given that,

and

We substitute these values into the above formula to obtain,

This implies that,

This simplifies to,


So we can now find

We use the same formula again,

We substitute the values to get,

We multiply out to get,
For this case we have the following expression:

We must find the value of the expression when:

Substituting the values in the expression we have:

Thus, the value of the expression is 2.
Answer:
The value of the expression is 2
Option A
Answer:
x=-1
Step-by-step explanation: