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3 years ago

What is the domain and range for the following function and its inverse?

Mathematics

1 answer:

Basile [38]3 years ago

4 0

Answer:

"f(x)

domain: all real numbers, range: all real numbers

f–1(x)

domain: all real numbers, range: all real numbers"

Step-by-step explanation:

We can use the fact that the domain of a function and the range of its inverse are equal.

Also, the range of the function and the domain of its inverse are equal as well.

Looking at the function f(x/ = -x + 5, we see that this is a line with a negative slope of 1 and a y-intercept of +5.

As we know from the graph of lines, there is no restricting values in x and y. So for the original function, domain is the set of all real numbers and the range is the set of all real numbers.

For the inverse, the range is set of all real numbers and domain is also the set of all real numbers.

First answer choice is right.

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d = 2r

Solving for 'd' (diameter)

d = C

π = 60

π ≈ 19.09859cm

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2 years ago

What is the answer for this problem if f(x)= 3x+10x and g(x)=5x-3, find (f+g)(x).

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3 years ago

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3 years ago

Galina is finding the area of triangle RST. To do so, she follows the steps in the table.

vladimir1956 [14]

1 step: to draw a rectangle around triangle RST, you should

draw points A(-1,-1), B(-1,3) and C(2,3);
connect points A, B, C and T consecutively.

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$A_{ABCT}=4\cdot 3=12$ sq. un.

3 step:

$A_{\triangle ART}=\dfrac{1}{2}AR\cdot AT=\dfrac{1}{2}\cdot 2\cdot 3=3$ sq. un.

$A_{\triangle BRS}=\dfrac{1}{2}BR\cdot BS=\dfrac{1}{2}\cdot 2\cdot 2=2$ sq. un.

$A_{\triangle SCT}=\dfrac{1}{2}CS\cdot CT=\dfrac{1}{2}\cdot 1\cdot 4=2$ sq. un.

4 step:

$A_{\triangle RST}=A_{ABCT}-A_{\triangle ART}-A_{\triangle BRS}-A_{\triangle SCT}=12-3-2-2=5$ sq. un.

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3 years ago

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Can someone simplify

Rashid [163]

Answer:

Option (2). $2\frac{1}{4}$

Step-by-step explanation:

The given expression is [ $-5\frac{1}{4}-(-7\frac{1}{2})$ ]

We can rewrite the fractions as,

$-5\frac{1}{4}$ = $-(5+\frac{1}{4})$

$-7\frac{1}{2}=-(7+\frac{1}{2})$

Now we will substitute the fractions in the expression,

$[-(5+\frac{1}{4})]-[-(7+\frac{1}{2})]$

= $-(5+\frac{1}{4})+(7+\frac{1}{2})$

= (-5 + 7) + $(-\frac{1}{4}+\frac{1}{2})$

= 2 + $\frac{2-1}{4}$

= 2 + $\frac{1}{4}$

= $2\frac{1}{4}$

Therefore, Option (2). will be the answer.

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3 years ago