Assuming we need to find i such that
1 ≤ i ≤ n and t[i]=i.
If we need to find only the first occurrence, we can do:
for i:1 to n {
if t[i]=i then return(i)
}
If exhaustive search is required, then put the results (values of i) in an array or a linked list, return the number of values found, and the array (or linked list).
3/4÷1/8 is the same as 3/4×8/1.
3×8=24
4×1=4
That becomes 24/4 which simplifies to 6. Your answer is 6.
F(g(x)) = f(3x+2) = h(x)=9x^2+12x + 6
Note that (3x+2)^2 = 9x^2 + 12x + 4, which is almost, but not quite, equal to h(x).
Let's experiment. What if f(x) = x^2 + 2?
Then f(3x+2) = (3x+2)^2 + 2 = 9x^2 + 12x + 4 + 2 = 9x^2 + 12x + 6, which is the same as the given h(x).
Thus, f(x) is x^2 + 2.
Answer:
sorry i cant figure this out
Answer:
912m
Step-by-step explanation:
There are two triangles.
The height of the triangles are 16m and the base is 12m.
Multiply 12(16)/2 to get the area of the triangle.
The area of the triangle is 96m.
Multiply 96 by 2 to get 192.
There are three rectangles.
Height is 20m and the base is 12m
20(12) is 240. Then, multiply by three.
240(3) is 720.
Add 192 and 720 to get 912m.
Hope this helps! Comment if I did something wrong.
