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Anvisha [2.4K]
3 years ago
7

The sides of rectangle feild (x+3)m and (x+7)m find the area of the feild

Mathematics
1 answer:
Ahat [919]3 years ago
3 0

Answer:

x^2+10x+21

Step-by-step explanation:

the area is <em>(x+3)(x+7)</em>

so it'll be: <em>x^2+10x+21</em> after you open it.

hope it'll help! have a good day!

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Christy drove 135 miles in 2.5 hours what was her average speed in miles per hour
vlada-n [284]
Her avarage speed in miles per hour is 54 
How i solved this was by 135/2.5 and i got 54
I hope this helps!
5 0
3 years ago
The diameter of a circle measures 32 mm. What is the circumference of the circle? Use 3.14 for , and do not round your answer. B
mart [117]

Answer:

100.48 ft

Step-by-step explanation:

8 0
3 years ago
The polynomial given below has _____ root(s).
lisov135 [29]
3x²-8x+4=0
(3x-2) (x-2)=0
x=2/3 ,  x = 2
Hence, the polynomial has two positive roots.
Option A is the correct choice.
8 0
3 years ago
A 12.5 oz bag of Doritos costs $3.79. A 3 oz bag costs $1.00. What is the difference in unit rates?
Furkat [3]

Answer:

0

Step-by-step explanation:

12.5/3.79 = 3.2981530343

3.2981530343 rounded = 3.3

1/3 = 3.33333333333333

3.33333333333333 rounded = 3.3

3.3 - 3.3 = 0

3 0
3 years ago
Read 2 more answers
Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than
liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

6 0
3 years ago
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