The slope of the line is 2. Why? Well, see below for an explanation!

The slope of a line is found by using the formula rise/run (rise over run). This means that by starting at the initial value of the y-intercept, 3, we would count how many units away we are from the next complete point. We do so by counting from left to right, and in this case, going up and then to the right. To get from the point (0, 3) to the point (1, 5), we would move two spaces vertically along the y-axis and one space horizontally along the x-axis. Because the slope of the line is found using the formula m = rise over run, the slope would be 2/1 because we went up 2 points and to the right one. When simplifying, we will find that 2 divided by 1 equals 2. Hence, our slope is 2.

Your final answer: The slope of the line is 2/1 or 2. If you need extra help, let me know and I will gladly assist you.

8 0

2 years ago

In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the

oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation(which is the square root of the variance) $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

$\mu = 503, \sigma = \sqrt{9604} = 98$

$Z = \frac{X - \mu}{\sigma}$

$1.476 = \frac{X - 503}{98}$

$X - 503 = 1.476*98$

$X = 648$

Abby's score

She scored 648.

$\mu = 521 \sigma = \sqrt{10201} = 101$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{648 - 521}{101}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

The percentle for Abby's score was the 89.62nd percentile.

3 0

3 years ago

At a local grocery store, bananas were on sale. Green bananas were priced at $14.00 and yellow bananas were priced at $12.00. Sa

garri49 [273]

Answer:

Sabrina bought 6 yellow bananas and 3 green bananas

Step-by-step explanation:

Let

Green bananas = x

Yellow bananas = y

Green bananas = $14.00

Yellow bananas = $12.00

Total cost = $114.00

x + y = 9 (1)

14x + 12y = 114 (2)

From (1)

x = 9 - y

Substitute x = 9 - y into (2)

14(9 - y) + 12y = 114

126 - 14y + 12y = 114

- 14y + 12y = 114 - 126

-2y = -12

Divide both sides by -2

y = -12 / -2

= 6

y = 6

Substitute y = 6 into (1)

x + y = 9

x + 6 = 9

x = 9 - 6

= 3

x = 3

Sabrina bought 6 yellow bananas and 3 green bananas

3 0

3 years ago

IaI − IbI + IcI , if a=−8; b=−5; c=1 pLEEEEEEZE hELP

yawa3891 [41]

Answer:

Step-by-step explanation:

to solve | a | - | b | + | c | we need to plug in the given values

a = -8

b = -5

c = 1

the | | bars mean absolute value which is the exact value a number is away from 0 on a number line. an absolute value has to be positive, not a negative, as you cant be negative spaces away from something. plugging in the values into the equation we have:

| -8 | - | -5 | + | 1 |

the absolute value of -8 is 8, as -8 is 8 units away from 0 on a number line

like wise with -5, the absolute value of -5 is 5, as -5 is 5 units away from 0 on a number line

1 is the absolute value of 1 as its 1 unit away from 0 on a number line

the new expression looks like the following:

8 - 5 + 1

now we just add/subtract

8 -5 = 3

3 + 1 = 4

the solution to this expression is 4

6 0

3 years ago