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3 years ago

Solve − 2 x − 10 y = 10

Mathematics

2 answers:

skad [1K]3 years ago

8 0

Answer:

x=-10 and y=1

Step-by-step explanation:

-2(-10)=20

-10(1)=-10

20-10=10

Mice21 [21]3 years ago

5 0

Step 1: isolate the "x" by bring everything else to the other side

$-2x-10y=10\\-2x= 10 +10y\\x= -5 -5y$

Step 2: The equation found above is the equation x is equal to so you plug it into all the x's the original equation to find y

$-2 (-5 - 5y) -10y = 10$

$10 + 10y -10y = 10\\10y - 10y = 0\\0y = 0\\y = 0$

Step 3: Plug in your newly found y (0) into the original equation to find the x

$-2x- 10(0) = 10\\-2x - 0 = 10\\-2x =10\\x = -5$

Hope this helped! Let me know if there is anything I need to clarify or explain more in depth!

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1 year ago

Solve the equation by showing the work X/3 -6 = -2

zavuch27 [327]

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Step-by-step explanation:

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3 years ago

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Which ordered pair is the solution to the system of equations? {y=3x−102x+3y=3

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3 years ago

Help math homework both questions

-Dominant- [34]

Answer:

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Step-by-step explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

Now, According to figure

Sin angle = $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$

Or, Sin Ф = $\dfrac{\textrm x}{\textrm e}$

Or, Sin 45° = $\dfrac{\textrm x meters}{\textrm 1.2 meters}$

Or, 0.707 × 1.2 meters = x

∴ x = 0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters . Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend = Ф = 22°

Let the glide runway path = y feet

Now, According to question

Tan angle = $\dfrac{\textrm perpendicular}{\textrm base}$

Or, Tan Ф = $\dfrac{\textrm H}{\textrm y}$

Or, Tan 22° = $\dfrac{\textrm 10,000 feet}{\textrm y feet}$

Or, 0.4040 = $\dfrac{\textrm 10,000 feet}{\textrm y feet}$

Or, y = $\dfrac{\textrm 10,000 feet}{\textrm 0.4040}$

∴ y = 24,752.47

So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer

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3 years ago