Is it 22m...look at the other side shouldn't it be the same (sorry if I didn't help :))))))))
Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have

Therefore, the probability of event A is given by

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Answer:
∠ADB ≅ ∠CBD
Step-by-step explanation:
The three arcs at each of D and B identify congruent angles. However, the angles cannot be identified by their vertices alone. The 3-letter designations of the congruent angles are ...
∠ADB ≅ ∠CBD
Answer:
m = - 7.5
Step-by-step explanation:
Given
9 + m = 1.5 ( subtract 9 from both sides )
m = - 7.5
So to answer you just have to substitute all the given choices into the formula and see which come out true.
2(1) - 3(-3) >_ 12
2 + 9 >_ 12
11 >_ 12
XNXOXPXEX
2(8) - 3(1) >_ 12
16 - 3 >_ 12
13 >_ 12
VYVEVSV
2(3) - 3(2) >_ 12
6 - 6 >_ 12
0 >_ 12
XNXOXPXEX
2(-2) - 3(-6) >_ 12
-4 + 18 >_ 12
14 >_ 12
VYVEVSV
2(2) - 3(3) >_ 12
4 - 9 >_ 12
-5 >_ 12
XNXOXPXEX
2(1) - 3(8) >_ 12
2 - 24 >_ 12
-22 >_ 12
XNXOXPXEX
2(-3) - 3(1) >_ 12
-6 - 3 >_ 12
-9 >_ 12
XNXOXPXEX
VYVEVSV = yes
XNXOXPXEX = nope