Post the problem directly in the question, thanks
<h2>Answer:</h2>
A.
Let Annie's weight be = a
Let Benjie's weighs = b
Let Carmen's weight be = c
One day Annie weighed 24 ounces more than Benjie, equation forms:
......(1)
Benjie weighed 3 1/4 pounds less than Carmen.
In ounces:
1 pound = 16 ounces
pounds =
ounces
or
......(2)
Now adding (1) and (2), we get
a+b=b+24+c-52
=> 
This gives Annie weighs 28 ounces less than Carmen.
B.
We cannot know anyone's actual weight, as we only know their relative weights.
Answer:
-6m^2 *n^2
Step-by-step explanation:
formula: (m^x)/(m^y)= m^(x-y)
apply formula for (4m^2)/(2m^-3)
=(4m^(2--3)/(2)
=4m^5/2
divide 4/2
=2m^5
next part 3n^5/(-mn)^3
3n^5/(-mn)^3
expand
=3n^5/ (-m^3*n^3)
=3n^(5-3)/ -m^3
=3n^2/ -m^3
both parts:
(2m^5* 3n^2)/ -m^3
= -(2m^5* 3n^2)/ m^3
= -(2m^(5-3)* 3n^2)/ 1
= -(2m^2* 3n^2)
= -(6m^2*n^2)
= -6m^2 *n^2
Here see the attachment....:)
All you have to do is to solve this problem is 60+2+0.20+0.02