You would set the problem into slope-interslope form : y = mx + b.
Slope (m) = rate of change b = y-intercept
Therefore, your in the above:
m = 3
b = 0
The constant proportionality (slope) is 3 and the y-intercept is 0.
Answer:
-4
Step-by-step explanation:
3.4+2(9.7-4.8x)=61.2
2(9.7-4.8x)=61.2-3.4
2(9.7-4.8x)=57.8
9.7-4.8x=57.8/2
9.7-4.8x=28.9
4.8x=9.7-28.9
4.8x=-19.2
x=-19.2/4.8
x=-4
F(x) = 25 - 2x
f(5) is pretty much the value of f(x) when x = 5
Plug x=5 into f(x)
f(5) = 25 - 2(5)
= 15
That's your answer.
Have an awesome day! :)
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
