The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.
<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>
Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.
On this note, since the task content suggest that the ratio of the perimeters is; 1:10, it follows from conventional mathematics that the ratio of their areas is given as; 1²:10²; 1:100.
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Answer:
C. 5√3
Step-by-step explanation:
To figure this out, we need to apply the Pythagorean Theorem, <em>a</em><em>²</em><em> </em><em>+</em><em> </em><em>b</em><em>²</em><em> </em><em>=</em><em> </em><em>c</em><em>²,</em><em> </em>where <em>c</em><em> </em>is the "HYPOTENUSE". In this case, <em>c</em><em> </em>is already found for us [10], so the operation we use whenever the hypotenuse is defined is deduction, or subtraction. Apply the Pythagorean Theorem: a² + 25 = 100; 75 = a². Now, to find <em>a</em><em>,</em><em> </em>we need to find two numbers that multiply to 75, where one of them is a PERFECT SQUARE, and in this case, they are 3 and 25. Since the square root of 25 is 5 [in this case, NO NON-NEGATIVE root], that gets moved to the outside of the radical, and 3 [NON-PERFECT SQUARE] stays wrapped under the radical, ending up with <em>5</em><em>√</em><em>3.</em><em> </em>You understand?
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Answer:
74
Step-by-step explanation:
fg(x)=f[g(x)]
=f(-4x+7)
=3(-4x+7)+5
=-12x+26
When x=-4,
fg(-4)=-12(-4)+26
=74
Answer: SIMPLIFY TERMS === 32X^3-12X^2+51X=35
Step-by-step explanation:
(4x2+x+7)(8x−5)
Expand (4x2+x+7)(8x−5)
by multiplying each term in the first expression by each term in the second expression.
4x2(8x)+4x2⋅−5+(x(8x)+x⋅−5)+(7(8x)+7⋅−5)
Simplify terms.
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32x3−12x2+51x−35
