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Charra [1.4K]
3 years ago
11

The Hawaiian language has 12 letters: five vowels and seven consonants. Each of the 12 Hawaiian letters are written on a slip of

paper and placed in the bag. A letter is randomly chosen from the bag and then replaced. Then, a second letter is randomly chosen from the bag. What is the probability that two vowels are chosen?
Mathematics
2 answers:
Murljashka [212]3 years ago
6 0

Answer:

\frac{25}{144}

Step-by-step explanation:

We want to know "probability that first is vowel AND second is vowel"

In probability theory, "AND" means Multiplication.

<em>Essentially we want to figure out probability of first drawn to be vowel and multiply that with probability second drawn is vowel as well.</em>

<em />

There are 5 vowels and total 12 letters, so

P (vowel) = 5/12

<u>For the second draw, there are STILL 12 letters and 5 vowels (since the first drawn is REPLACED)</u>. Hence, probability of 2nd vowel is the same. So:

P (vowel for 2nd draw) = 5/12

<em>Now we multiply them to get:  \frac{5}{12}*\frac{5}{12}=\frac{25}{144}</em>

larisa86 [58]3 years ago
3 0

Answer:

0.17

Step-by-step explanation:

Given in the question that,

number of vowels in Hawaiian language = 5

total number of letters in Hawaiian language = 12

Probability = favourable outcome / total number of outcome

probability that first letter is vowel = 5/12

probability that second letter is vowel = 5/12

<em>(since the first drawn was replaced)</em>

probability that two vowels are chosen = (5/12)(5/12)

                                                                  = 0.17

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