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Viktor [21]
3 years ago
8

Is (x + 7) a factor of f(x) = x3 − 3x2 + 2x − 8? Use either the remainder theorem or the factor theorem to explain your reasonin

g
Mathematics
1 answer:
guajiro [1.7K]3 years ago
4 0

Step-by-step explanation:

If x + 7 is a factor of f(x), then f(-7) = 0.

f(-7) = (-7)³ − 3(-7)² + 2(-7) − 8

f(-7) = -343 − 147 − 14 − 8

f(-7) = -512

x + 7 is not a factor of f(x).

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3 years ago
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A train is traveling at a constant speed and goes 7.5 kilometers in 6 minutes. At that rate:
Semenov [28]

Answer:

it goes 1.25 km per minute

Step-by-step explanation:

7.5 divided by 6=1.25

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3 years ago
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Which expression is<br>equivalent to 3(X-4)​
agasfer [191]
Answer:
3x - 12 is an expression equivalent to 3(x - 4)

Explanation:
Another way to write this expression is to simplify it. To simplify the given expression, multiply the number three by the x and negative four inside the parentheses.

3(x - 4)
3x - 12

Therefore, 3x - 12 is the simplified version of the expression 3(x - 4). In other words, 3x - 12 is an expression equivalent to 3(x - 4).
5 0
3 years ago
Enter numbers to evaluate ‐13−23.
Nana76 [90]

Answer:

- 13 - 23 = - 13 + (-23)

= -36

- 13 - (- 23) = - 13 + 23

= 10

Step-by-step explanation:

In any order of operation (i.e. addition, subtraction, multiplication, devision) the following rules apply for two values for instance <em>a </em>and <em>b </em>where <em>a > b </em>:

→ <em>If +a and +b then the final sign will be + (positive)</em>

→ <em>If +a and -b then the final sign will be + (positive) since a>b</em>

→ <em>If -a and +b then the final sign will be - (negative) since a>b</em>

→ <em>If -a and -b then the final sign will be - (negative)</em>

In the given question we have two cases.

Case 1:

- 13 - 23 = - 13 + (-23)     <em>→ since it is given that we add a negative value of -23, therefore it keeps its sign (so this would be a negative addition i.e. adding two negative values)</em>

Thus we have:

- 13 - 23 = - 13 + (-23)

= -36

Case 2:

- 13 - (- 23) = - 13 + 23     <em>→ since we stated earlier that - and - gives positive sign (i.e. we subtract two negative values)</em>

Thus we have:

- 13 - (- 23) = - 13 + 23

= 10

<em>So we can see that: </em>

<em>Adding two Negative values gives a Negative value (Case 1)</em>

Subtracting two Negative values gives a Positive value (Case 2)

6 0
3 years ago
P.S ( The calculator given to me doesnt work ;-; ) NEED HELP ASAP FOR MY HOMEWORK ASSIGNMENT!! IF YOU ANSWER RIGHT ILL MARK YOU
wolverine [178]

Answer for the first box:  20

Answer for the second box: 6

====================================================

Explanation:

The notation a(1) represents the first term of the sequence given. The first term is 20, so thats why a(1) = 20.

The notation a(n) = a(n-1) + ____ means we add some term to the previous term to get the next. This process happens over and over. In this case, we add 6 to each term to get the next

  • term1 = 20
  • term2 = term1 + 6 = 20 + 6 = 26
  • term3 = term2 + 6 = 26 + 6 = 32
  • term4 = term3 + 6 = 32 + 6 = 38

and so on...

So we write a(n) = a(n-1) + 6

This value of 6 can be found by selecting any term and subtracting off the previous term, so we could say any of the following below

  • term2 - term1 = 26 - 20 = 6
  • term3 - term2 = 32 - 26 = 6
  • term4 - term3 = 38 - 26 = 6

That's how we end up with

\begin{cases}a(1) = 20\\a(n) = a(n-1) + 6\end{cases}

-------------------------

Extra info:

The common difference is d = 6 and the first term is a = 20

We can use these two facts to find the nth term a(n)

a(n) = a + d*(n-1)

a(n) = 20 + 6*(n-1)

a(n) = 20 + 6n - 6

a(n) = 6n + 14

Then note how plugging in n = 1 leads to

a(n) = 6*n + 14

a(1) = 6*1 + 14

a(1) = 20

and n = 2 leads to

a(n) = 6*n + 14

a(2) = 6*2 + 14

a(2) = 26

and so on

This allows us to plug in any value of n we want, without having to generate the previous terms before it. So for instance, you could plug in n = 100 to jump directly to the 100th term. If you use the recursive definition in the last section, then you have to generate the first 99 terms first before you can get to the 100th term.

7 0
3 years ago
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