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vekshin1
2 years ago
13

What is the GCF of 2+18+40

Mathematics
2 answers:
tiny-mole [99]2 years ago
7 0
2 my friend..........
vlabodo [156]2 years ago
6 0
2 is the GCF of <span>2+18+40
.</span>
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HELP ASAP!! please help me answer 2 and 5.
irga5000 [103]

Answer:

b

Step-by-step explanation:

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2). Acceleration is also a vector quantity, so it includes both magnitude and direction.

3 0
2 years ago
Suppose that the mean time that visitors stay at a museum is 94.2 minutes with a standard deviation of 15.5 minutes. The standar
Maurinko [17]

Answer:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

Step-by-step explanation:

For this case we know that mean time that visitors stay at a museum is given by:

\bar X = 94.2

The standard deviation is given by:

s= 15.5

And the standard error is given by:

SE = \frac{s}{\sqrt{n}} =3.1

And we want to interval captures 68% of the means for random samples of 25 scores and for this case the critical value can be founded like this using the normal standard distribution or excel:

z_{\alpha/2}= \pm 0.994

We can find the interval like this:

\bar X \pm ME

And replacing we got:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

7 0
3 years ago
Please help urgently ​
jenyasd209 [6]

Answer: no real solution

Thus, the function has no x- intercept

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What is dy/dx if y = (x2 + 2)3(x3 + 3)2? A. 3(x2 + 2)2(x3 + 3)2 + 2(x2 + 2)2(x3 + 3) B. 2x(x3 + 3)2 + 3x2(x2 + 2)3 C. 6x(x2 + 2)
Vlada [557]
We want to find \displaystyle{  \frac{dy}{dx}, for

            \displaystyle{ y=(x^2+2)^3(x^3+3)^2.

Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:

                                  (fg)'=f'g+g'f.

Thus,

 y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3

Answer: A)      3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3.



8 0
3 years ago
What’s all input for f(x)=3
defon

Answer:

all inputs are equal to <u>3</u>

Step-by-step explanation:

f(x) = 3 \\  =  3 \times 1\\  = 3  \times  {x}^{0}  \\ anything \: raised \: to \: 0 \: is \: 1 \\

\\  substituting \: any \: value \\  \: of \: x \: in \: f(x) \\ f(3) = 3 \times  {3}^{0}  \\  = 3 \times 1 \\ =  3 \\

\\ similarly \: all \: values \: of \: x \: will \\ give \: 3

8 0
2 years ago
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