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ArbitrLikvidat [17]
3 years ago
15

At a supermarket salad bar, the price of a salad depends on its weight. Salad costs $.19 per ounce. Write a rule to describe the

function. How much would an 8-ounce salad cost?
Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0

Answer:

For an 8-ounce salad would cost $1.52

Step-by-step explanation:

Every ounce would cost $0.19.

So you would multiply the cost with how much you would buy.

0.19(cost per ounce)×8(how much ounce)=1.52(total pay)

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A number r is more than 0 or less than or equal to ‐8
Butoxors [25]

Answer

-8 \geq r > 0

Step-by-step explanation:

you know that r is less than or equal to -8, so you write that, and then you know that r is also greater than 0, so then you add that to it, and then you have the answer. r will be in the middle because it is the range of what are can be.

7 0
3 years ago
Can you Please Help ASAP!
marin [14]
THE ANSWER IS 70 !!

When you add up all the sides to get 290 and the total amount of the angles is 360 so you subtract 290-360 and you get 70
4 0
3 years ago
What is the formula for finding the height of a cylinder?
andrezito [222]
H= volume/ pi(r)^2 is the height of a cylinder
3 0
3 years ago
Read 2 more answers
Use a double angle identity to rewrite the formula r(Θ)=<img src="https://tex.z-dn.net/?f=1%2F16v%5E2sin%28theta%29cos%28theta%2
Artist 52 [7]

Answer:

1/32v²sin2θ

Step-by-step explanation:

Given the expression r(theta) = 1/16v²sinθcosθ

According to double angle of trigonometry identity;

Sin2θ = sin(θ+θ)

Sin2θ = sinθcosθ + cosθsinθ

Sin2θ = 2sinθcosθ

sinθcosθ = sin2θ/2 ... **

Substituting equation ** into the question

1/16v²sinθcosθ = 1/16v²(sin2θ/2)

1/16v²sinθcosθ = 1/2×1/16v²(sin2θ)

1/16v²sinθcosθ = 1/32v²sin2θ

Hence using the double angle identity, the equivalent expression is 1/32v²sin2θ

7 0
3 years ago
2x2 – 9x + 2 = –1
Reika [66]

Answer:

C)  The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0

\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}

\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}

\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}

2x^2-9x+2=-1

\implies 2x^2-9x+3=0

\implies a=2, b=-9, c=3

\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}

5 0
2 years ago
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