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Dmitrij [34]
3 years ago
5

A group of 10 fisherman enjoy certain types of fish, 3 of them like salmon, 5 like trout and 2 like bass. A single fisherman is

chosen at random. What is the probability that the fisherman likes salmon or bass?
A. 1/10
B. 47/90
C. 3/50
D. 1/2
Mathematics
2 answers:
Anna35 [415]3 years ago
6 0
The answer is D. 1/2
Marina CMI [18]3 years ago
3 0

Answer:

Option D.

Step-by-step explanation:

From given information it is clear that

Total number of fisherman = 10

Who like salmon fish = 3

Who like trout fish = 5

Who like bass fish = 2

We need to find the probability that the fisherman likes salmon or bass.

Probability=\dfrac{\text{Who like salmon fish + Who like bass fish}}{\text{Total number of fisherman}}

Probability=\dfrac{3+2}{10}

Probability=\dfrac{5}{10}

Probability=\dfrac{1}{2}

Therefore, the correct option is D.

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Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

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\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2

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$\csc\theta =\frac{18}{4\sqrt{14} }

$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}

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$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}

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$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}

$\tan \theta=\frac{4\sqrt{14} }{10}

$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}

$\cot \theta=\frac{10}{4\sqrt{14} }

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