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Evaluate bd for a = 5, b = -2, c = 4 and d = -6. user: perform the indicated operation. (-50) �� (-2) user: perform the indicate

Stella [2.4K]

Assuming that the missing operations are multiplication as it is with the first question "bd", then the answer would be as follows:

1.) Simply substitute the values of b and d before multiplying.

bd = (-2)(-6) = 12

2.) (-50)(-2) = 100

3.) (5/8)(7/12)= 35/96

7 0

2 years ago

How many centimeter squares would be wrapped around this rectangular prism?

denis23 [38]

You haven't told us whether the rectangular prism is the size of a pack of gum or more like the size of a cruise ship.

Whatever size it is, here's the number of centimeter squares you need to cover the whole outside of it:

(2 x length x width) + (2 x length x height) + (2 x width x height)

with all measurements made in centimeters.

4 0

3 years ago

What are the equivalent ratios shown in the table?

GarryVolchara [31]

Answer:

These are all equivalent to the ratio of 1:2

Step-by-step explanation:

4 0

2 years ago

In ΔCDE, the measure of ∠E=90°, DE = 39 feet, and CD = 89 feet. Find the measure of ∠C to the nearest degree.

Nonamiya [84]

It’s 64.4 :)
i just did it lolz

8 0

3 years ago

Read 2 more answers

Home CoworkHelper

9966 [12]

Answer:

See below.

Step-by-step explanation:

PROBLEM A

The formula for the volume of a cylinder is

V = πr²h, where πr² is the area of the base.

V = area of base x height

Choose any four numbers that are less than 10 for the height.
Then, substitute into the formula and isolate "r". 10 = πr²h
Double "r" to find the diameter.
The area of the base is found (bolded) while you solve πr².

*I will use the calculator button for pi (π)

Cylinder A: h = 1

10 = πr²h

10 = πr²(1)

10 = πr² Area of the base is 10m².

r = √ (10/π)

r = 1.78 Radius is 1.78m.

d = 2r = 1.78*2 = 3.56 Diameter is 3.56m.

Cylinder B: h = 2

10 = πr²h

10 = πr²(2)

5 = πr² Area of the base is 5m².

r = √ (5/π)

r = 1.26 Radius is 1.26m.

d = 2r = 1.26*2 = 2.52 Diameter is 2.52m.

Cylinder C: h = 4

10 = πr²h

10 = πr²(4)

2.5 = πr² Area of the base is 2.5m².

r = √ (2.5/π)

r = 0.89 Radius is 0.89m.

d = 2r = 0.89*2 = 1.78 Diameter is 1.78m.

Cylinder D: h = 5

10 = πr²h

10 = πr²(5)

2 = πr² Area of the base is 2m².

r = √ (2/π)

r = 0.80 Radius is 0.8m.

d = 2r = 0.80*2 = 1.6 Diameter is 1.6m.

The answers are reasonable if the answer is close to 10 when you substitute the rounded numbers back into the formula and solve.

There are infinite possibilities because any numbers when used in the formula equates to 10 are possible. The height/radius can be any decimal number, which would make the other dimensions change.

PROBLEM B

Follow similar steps if you know the diameter of a cylinder. Use the same formula V = πr²h.

We need the radius, which is half the diameter. r = d/2 = 10/2 = 5

Choose a random number for volume that divides easily by 25.
Substitute "V" and "r²" (r² = 25).
Isolate "h".
The area of the base is 78.54 cm² every time (A = πr²).

Cylinder A: V = 100

100 = π25h

4 = πh

h = 1.27 The height is 1.27m.

Cylinder B: V = 200

200 = π25h

8 = πh

h = 2.55 The height is 2.55m.

Cylinder C: V = 75

75 = π25h

3 = πh

h = 0.95 The height is 0.95m.

Cylinder D: V = 125

125 = π25h

5 = πh

h = 1.59 The height is 1.59m.

The answers are reasonable if I can substitute two rounded values into the formula and get a number close to the third. The height is also a decimal number which occurs because of pi.

6 0

3 years ago