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lubasha [3.4K]
2 years ago
5

Given the points (0,−3) and (5,-6) and on a line, find its equation in the form y=mx+b

Mathematics
1 answer:
Andrew [12]2 years ago
4 0

Answer:

Step-by-step explanation:

y=mx+b

b=-3 (y intercept)

Use equation y2-y1/x2-x1

-3/5= m

y=-3/5x-3

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The sum of 237 and six times the opposite of a number is 405. What is the number?
Bond [772]

Answer:

(A) x=-28

Step-by-step explanation:

237 -6x = 405           [note that 6*(-x) is (-6x)]

  -6x = 168           [subtract 237 from both sides]

   x = -28             [divide both sides by (-6)]

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Given below are some inequalities. Plot the feasible region graphically.
igor_vitrenko [27]

Answer:

0-89x=78/-43

Step-by-step explanation:

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Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F
Svet_ta [14]

Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

y = 2x + 12

The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

x^{2} = 0

x_{1}  = 3\\x_{2}  = -3

To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

3 0
2 years ago
9x – 7 = 9x + h<br> What dose h equal to
deff fn [24]

Answer:

h= -7

hope this helps!!:)

Step-by-step explanation:

4 0
2 years ago
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