Answer:
$30341.88
Step-by-step explanation:
Because it says simple interest, use the formula I = Prt.
(I is interest, r is the % rate as a decimal, t is the time)
So, you have to solve the equation,
1755 = P (0.065)(9)
Since 0.065 x 9 = 0.585, the equation can be simplified to
1755 = 0.585P
Then, to get P, you divide both sides by 0.585
P = 1755/0.585 = $30341.88
I'm going to separate this into sections so it makes more sense for you to read. For the problems with π where you have to round, ask your teacher where to round, unless your textbook specifies it:
A – 100 cm^2
To calculate area of squares, you multiply l • w. It's a square, so all sides are equal, and since we know that one side = 10 cm, the area is 10 • 10 = 100
B – πr^2 (not sure if the r shows up very well, so I'm retyping it in words - pi • radius squared)
C – 25π cm^2 or an approximate round like 78.54 cm^2 (ask your teacher about this – it could be to the nearest tenth, hundredth, etc.)
To find the area of a circle, you must follow the formula πr^2. In this case, the diameter is 10. The radius is half the diameter, so to substitute the values you must find 10 ÷ 2 = 5. So the radius is 5 cm. From there you can substitute r for 5, ending up with π • 5^2. 5^2 = 25, so the area is 25π, or about 78.54, depending on where the question wants you to round.
D – An approximate round (to the nearest hundredth it is 21.46 cm^2)
To find the area of the shaded region, just subtract the circle's area from the square's area, or 100 – 25π ≈ 21.46. Again, though, ask your teacher about where to round, unless your textbook specifies it.
E – dπ (diameter • pi)
F – 10π cm^2 or an approximate round like 31.42 cm^2
The diameter is 10. 10π ≈ 31.42
Hope this helps!
B=36
prisms give me the most difficulty
If you would like to know the bike wheel's diameter in millimeters, you can calculate this using the following steps:
26 inches in diameter
1 inch = 25.4 millimeters
26 inches = 26 * 1 inch = 26 * 25.4 millimeters = 660.4 millimeters
The correct result would be 660.4 millimeters in diameter.
