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AleksandrR [38]
3 years ago
6

Can anyone please help me on this question

Mathematics
2 answers:
ELEN [110]3 years ago
6 0
D

distribute negative sign first

5x +3 +-1(x+2
5x+3+-1x+(-1)(2)
5x +3-x+-2

now combine like terms
( 5x + -x) + (3 + -2)

4x+1
Setler79 [48]3 years ago
3 0

Answer:

d

Step-by-step explanation:

(5x + 3 ) - (x + 2 )

distribute (5x + 3) by 1 and (x - 2) by - 1

= 5x + 3 - x - 2 ← collect like terms

= 4x +1 → d


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Answer:

One way to factor equation is to find the zeros. Its obvious that x=-1 is solution for this. So one factor is (x+1)

the next factor should include 2x at first (because we have 2x^2 in the equation which can not be made any other way)

Let's suppose the factor is (x+1)(2x+b)

Since we do not know what is b open the brackets 2x^2+bx+2x+b. If this is equal to 2x^2+5x+3 then b=3. We are left with (x+1)(2x+3)=2(x+1)(x+3/2)

Would go for other shorter solutions, but they require some deeper understanding like Horner's scheme,Fermat's Theorem or even deeper which I assume You will not understand)

8 0
3 years ago
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german

Answer:

\frac{32}{3}

Step-by-step explanation:

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4^{4} is basically 4 × 4 × 4 × 4, which can simplify to 256.

So,  \frac{4^{4}}{4!} = \frac{256}{24}.  \frac{256}{24} can simplify to \frac{32}{3}. Therefore,  \frac{4^{4}}{4!} = \frac{32}{3}.

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Have a great day!

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