All categories

3 years ago

What 3 digits are in the units period 4,083,817

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

6 0

So the answers 3,000 cause it said period i mean unit period

marysya [2.9K]3 years ago

5 0

It would be 3,000! I'm sure it is... because it says Unit Period :)

You might be interested in

A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 3 : 1.

S_A_V [24]

Coordinates of point C: (1,-1)

Step-by-step explanation:

In this problem, A, B and C are collinear, and B is between A and C.

The ratio AB : BC is 3 : 1.

This means that we can write the following two equations:

$x_B-x_A = 3(x_C-x_B)\\y_B-y_A=3(y_X-y_B)$

where:

$(x_A,y_A)=(-7,3)$ are the coordinates of point A

$(x_B,y_B)=(-1,0)$ are the coordinates of point B

$(x_C,y_C)$ are the coordinates of point C

Solving the equation for $x_C$ ,

$x_C = x_B + \frac{x_B-x_A}{3}=-1+\frac{-1-(-7)}{3}=1$

Solving the equation for $y_C$ ,

$y_C=y_B + \frac{y_B-y_A}{3}=0+\frac{0-3}{3}=-1$

So, the coordinates of point C are

$C(-1,1)$

Learn more about how to divide segments:

brainly.com/question/3269852

brainly.com/question/11280112

#LearnwithBrainly

4 0

3 years ago

Are z³ and 3z equivelent?explain

salantis [7]

Yes because you are multiplying 3 z’s and also 3z’s

7 0

3 years ago

The length of a rectangle is 3 inches more than twice its width, and its area is 65 square inches. What is the width?

tino4ka555 [31]

That makes no sense, what DO you get?

The correct answer is, A, or question 1, or 2w + 3.

Go ahead and click that like button and why don't you rate 5 stars as well!:)

My profile name is SweetyPie12, why don't you hit that friend request button!:)

YEAHHHHHH!

lol ;)

7 0

3 years ago

The sum of two numbers is 98 and the difference between them is 48. find the two numbers.

zavuch27 [327]

So first what you want to do is take 98 and subtract it by 48. Which gives us 50. Now what we do is that since we are finding two numbers we would have to divide that by half, which would give us 25. Both of them are now equal. To find the number that makes that difference, we need to add 48 to one of the 25 values. Which would be 73. Meaning that the two numbers are 73 and 25. They both add up to 98 and 73 has a difference of 48 from 25.

3 0

3 years ago

13 POINTS- please help me

allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

Then

$(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}$

17. Two parallel lines are cut by transversal. Angles with measures $(2x+12)^{\circ}$ and $(3x-22)^{\circ}$ are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

$2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34$

Then

$(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}$

18. Two parallel lines are cut by transversal. Angles with measures $(6x-7)^{\circ}$ and $(5x+10)^{\circ}$ are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

$6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17$

Then

$(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}$

19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

Hence,

$2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}$

Check:

$34^{\circ}+56^{\circ}=90^{\circ}$

20. Angles $\angle 1$ and $\angle 2$ are vertical angles. By vertical angles theorem, vertical angles are congruent, so

$m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4$

Hence,

$m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}$

21. $\angle 5$ and $\angle 8$ are supplementary. The measures of supplementary angles add up to $180^{\circ},$ so

$m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34$

Therefore,

$m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}$

7 0

3 years ago