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lbvjy [14]
3 years ago
13

Who wants to talk? I am willing to talk to anyone! I AM SO BORED!!

Computers and Technology
2 answers:
wolverine [178]3 years ago
4 0

Answer:

I want to talk. Im bored too

Explanation:

satela [25.4K]3 years ago
3 0

I'd love to talk with you :)

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Which of these statements regarding mobile games is true? A. They are typically played indoors. B. They have detailed environmen
Lyrx [107]

Answer:

c and d

Explanation:

6 0
3 years ago
The L-exclusion problem is a variant of the starvation-free mutual exclusion problem. We make two changes: as many as L threads
vladimir2022 [97]

Answer:

The solution is as follows.

class LFilters implements Lock {

int[] lvl;

int[] vic;

public LFilters(int n, int l) {

lvl = new int[max(n-l+1,0)];

vic = new int[max(n-l+1,0)];

for (int i = 0; i < n-l+1; i++) {

lvl[i] = 0;

}

}

public void lock() {

int me = ThreadID.get();

for (int i = 1; i < n-l+1; i++) { // attempt level i

lvl[me] = i;

vic[i] = me;

// rotate while conflicts exist

int above = l+1;

while (above > l && vic[i] == me) {

above = 0;

for (int k = 0; k < n; k++) {

if (lvl[k] >= i) above++;

}

}

}

}

public void unlock() {

int me = ThreadID.get();

lvl[me] = 0;

}

}

Explanation:

The code is presented above in which the a class is formed which has two variables, lvl and vic. It performs the operation of lock as indicated above.

6 0
3 years ago
A palindrome number is a number that remains the same when its digits are reversed. Like 16461, for example, is a palindrome num
xxMikexx [17]

Answer:

Code is given below and output is attached as an image.

Explanation:

#include <iostream>

#include <fstream>

using namespace std;

bool isPalindrome(int n)

{

       // Find reverse of n

       int rev = 0;

       for (int i = n; i > 0; i /= 10)

               rev = rev * 10 + i % 10;

       // If n and rev are same,then n is a palindrome

       return (n == rev);

}

int main()

{

       int min = 1;        // Lower Bound

       int max = 200;      // Upper Bound

       ofstream myfile;

       myfile.open("palindrome.txt");

       for (int i = min + 1; i < max; i++)

               if (isPalindrome(i))

                       myfile << i << endl;

       myfile.close();

       return 0;

}

5 0
3 years ago
HELP PLSSSSS!!! I WILL MARK BRAINLIEST FOR THE FIRST AND CORRECT ANSWER!!!
dalvyx [7]
The answer you are looking for would be A. Hardware can be an external tool, where as software is an internal tool. Hope this helped!
6 0
3 years ago
Read 2 more answers
Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
Gnoma [55]

Answer:

public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

       }

       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

Explanation:

Using Java prograamming Language.

The Method (function) print_popcorn_time is defined to accept a single parameter of type int

Using if...else if ....else statements it prints the expected output given in the question

A complete java program calling the method is given below

public class num6 {

   public static void main(String[] args) {

       int bagOunces = 7;

       print_popcorn_time(bagOunces);

   }

   public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

       }

       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

}

3 0
3 years ago
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