Question

We will pass you 2 inputsan list of numbersa number, N, to look forYour job is to loop through the list and find the number specified in the second input. Output the list element index where you find the number.If N is not found in the list, output -1.Tip: Remember the break statement? It exits the loop. You can (but don’t have to) use this.# Get our input from the command lineimport sysN= int(sys.argv[2])# Convert the list of strings into integersnumbers= []for i in sys.argv[1].split(","):if(i.isdigit()):numbers.append(int(i))# numbers now contains the list of integers# Write your code below

Answer 1

Answer:

The Python code is given below

Explanation:

# Get our input from the command line

import sys

N = int(sys.argv[2])

# Convert the list of strings into integers

numbers= []

for i in sys.argv[1].split(","):

   if(i.isdigit()):

       numbers.append(int(i))

# numbers now contains the list of integers

f = False

#Use for loop upto len(numbers)

for i in range(0,len(numbers)):

   #Use "if" loop to check

   if numbers[i] == N:

       #Assign "True" to "f"

       f = True

       #Display "i"

       print(i)

       break

#Check "if" loop by assigning "false" to "f"

if f==False:

   #Print "-1"

   print("-1")