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3 years ago

I need help with this math question

Mathematics

1 answer:

Vitek1552 [10]3 years ago

3 0

Ava took 5 minutes out of 60 in an hour to do half a mile
5×2=10
60/10=6mph

Damon took 3 minutes out of 60
3×2=6
60/6= 10mph

Reina took 4 minutes out of 60
4×2=8
60/8= 7.5mph

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If the area of a right-angled triangle is 47 56 cm and its height is 11.6 cm. finds its base.

Wewaii [24]

Answer:

820

Step-by-step explanation:

Hi so if your area is 4756, the base would be 820

8 0

2 years ago

Find the diameter of a circle with a circumference of 443 feet. Use 3.14 for pi.

marishachu [46]

Answer:

$\huge\boxed{\sf d = 141\ feet}$

Step-by-step explanation:

<u>Given Data:</u>

Circumference = C = 443 ft

<u>Required:</u>

Diameter = d = ?

<u>Formula:</u>

d = C / π

<u>Solution:</u>

d = 443 / 3.14

d = 141.0 feet

d = 141 feet

$\rule[225]{225}{2}$

Hope this helped!

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1 year ago

Read 2 more answers

If 75 equals a number plus four times the number, find the number

olga nikolaevna [1]

X + 4x = 75
Combine like terms:
5x = 75
Divide by 5 on each side of the equal sign:
x = 15

7 0

2 years ago

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consuela earns a salary of $40,000 per year plus a commission of $1000 for each car she sells right and solve an equation that s

musickatia [10]

The equasion she would use would be 60,000 = 1000x + 40,000

this would means 1,000 times a number plus the 40,000 shes already getting equals 60,000

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3 years ago

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A small airline overbooks flights on the assumption that several passengers will not show up. Suppose that the probability that

olchik [2.2K]

We have 22 tickets sold, and 20 seats. This means that at least 2 passengers must not show up (otherwise, at least 21 passengers will be present, and there wouldn't be space for them).

Considering each passenger as independent, you can think of this experiment. Suppose you toss a coin for each passenger. If the coin lands on heads, the passenger shows up. If it lands on tails, the passenger doesn't show up.

But the coin is unfair: it has a 0.91 probability of landing on heads, and thus 0.09 probability of landing on tails.

This implies that the probability of having exactly $k$ tails is

$\binom{22}{k} \cdot 0.09^k \cdot 0.91^{22-k}$

We already concluded that at least two passengers must not show up. So, if our coins lands on tails less than twice, we've lost. So, the losing probability is

$\displaystyle\binom{22}{0}\cdot 0.09^0 \cdot 0.91^{22} + \binom{22}{1}\cdot 0.09^1 \cdot 0.91^{21} \approx 0.39$

Finally, remember the rule to negate events:

$P(E) = 1-P(\lnot E)$

So, if we lose with probability 0.39, we win with probability

$1-0.39 = 0.61$

6 0

3 years ago