We've hit on a case where a measure of center does not provide all the information spread or variability there is in month-to-month precipitation. based on how busy each month has been in the past, lets managers plan
Answer:
2.5 pi
Step-by-step explanation:
Comment
If you were trying to get the area of a whole circle, you would use
Area = pi r^2
You have to modify the formula to show that just part of the circle has an area that you are interested in.
The new formula is
Area = (theta/360) pi r^2
Givens
r = 30 cm
theta = 100
Solution
Area = (100 / 360) * pi * r^2 Substitute the givens into this formula
Area = (5 / 18) * pi * 3^2 Expand
Area = (5 / 18) * pi * 9 Cancel 9 into 18
Area = 5/2 * pi
Area = 2.5 * pi
Answer:

Step-by-step explanation:
<u><em>The question in English is </em></u>
An expanding mobile phone company handled eight hundred and fifty thousand calls a day during the quarter. In the next quarter it expects to reach one million and increase quarterly by the same amount over the next two years. How many daily calls do you expect to handle in two years?
Let
x ----> the number of quarter
y ---> number of daily calls
we know that
we have the points
(0,850,000) and (1,1,000,000)
Find the slope m

The linear equation that represent this situation is

How many daily calls do you expect to handle in two years?
In two years there are 8 quarterly
so
For x=8
substitute

4x+y = 3
if x = 0, y = 3
ordered pair (0,3)