Answer
Perimeter = 1.75 times larger
Area = 3.0625 times larger
Step-by-step explanation:
Let the original quadrilateral have sides of a, b, c, d
Perimeter of the New Photograph
- Then the perimeter of the original is P = (a + b + c + d)
- Now the perimeter of the new quad is P = 1.75a + 1.75b + 1.75c + 1.75d
- Using the distributive Property we get P = 1.75(a + b + c + d) So the new perimeter is 1.75*the old perimeter.
Area of the New Photograph
The area is a little harder. Suppose the Old figure had an Area found by the formula of
- Area = e * f Each measurement is increased by a factor of 1.75
- Area_new = 1.75e * 1.75f
- Area_new = 3.0625 * e * f
- Area_new = 3.0625 * old area
Where the two lines intersect is your solution.
Answer:
6 lengths
Step-by-step explanation:
You essentially want the smallest integer solution to ...
60x ≥ 350
x ≥ 350/60
x ≥ 5 5/6
The smallest integer solution to this is x = 6.
The minimum number of lengths of hose needed is 6.
_____
Informally, you know that dividing the required total length by the length of one hose will tell you the number of required hoses. You also know the ratio 350/60 is equivalent to 35/6 and that this will be between 5 and 6. (5·6 = 30; 6·6 = 36) The next higher integer value will be 6.
The number is 'n'.
Five times the number is 5n .
Nine more than that is 5n + 9 .
