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quester [9]
3 years ago
6

Kermit's favorite iced tea is made with 15 tea bags in every 2 liters of water. Peggy made a 12-liter batch of iced tea with 90

tea bags. What will Kermit think of Peggy's iced tea? Choose 1 answer: Choose 1 answer: (Choice A) A It is too strong. (Choice B) B It is too weak. (Choice C, Checked) C It is just right.
Mathematics
2 answers:
Finger [1]3 years ago
7 0

Answer:

the answer is C it is just right

Step-by-step explanation:

stepan [7]3 years ago
5 0

Number of tea bags need to make for every 2 liters of water = 15 tea bags.

For each liter of water there need = 15/2 = 7.5 tea bags.

Peggy need to make 12 liters of iced tea.

<em>Therefore, total number of tea bags required for 12 liters of iced tea = 12 × 7.5 </em>

<em>= 90 tea bags.</em>

Peggy also took 90 tea bags to make a 12-liter batch of iced tea.

<h3>Therefore, correct option is C option.</h3><h3>C It is just right.</h3>
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3 years ago
A solid oblique pyramid has a regular hexagon base with an area of 54_/3 cm^2 and an edge length of 6cm. Angle BAC measures 60 d
Lady_Fox [76]

Answer: The answer is (C) 324 cubic cm.


Step-by-step explanation: As given in the question, given a solid oblique pyramid with a regular hexagonal base and area 54√3 cm². Also, the edge length of the base is 6cm and ∠BAC = 60°.

We are to find the volume of the pyramid.

The formula for finding the volume of a pyramid is given by

V=\dfrac{1}{3}b\times h,

where, 'b' is the base area and 'h' is the perpendicular height of the pyramid.

Here, b = 54√3 cm², h = ?

Now, from the right-angled triangle ABC, we have

\dfrac{\textup{BC}}{\textup{AC}}=\tan 60^\circ\\\\\Rightarrow \dfrac{h}{6}=\sqrt 3\\\\\Rightarrow h=6\sqrt 3.

Therefore, the volume of the pyramid is

V=\dfrac{1}{3}b\times h=\dfrac{1}{3}\times 54\sqrt 3\times 6\sqrt 3=324.

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3 years ago
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Step-by-step explanation:

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Choose the correct simplification of f^9 h^23/f^3 h^17
Tanzania [10]

Answer:

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Step-by-step explanation:

Step  1  :

           h23

Simplify   ———

           f3  

Equation at the end of step  1  :

         h23

 ((f9) • ———) • h17

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Step  2  :

Multiplying exponential expressions :

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Final result :

 f6h40

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3 years ago
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