Find an equation of the line that is perpendicular to the graph of 2x+5y=5 and contains the point of intersection of the graphs
of y=x+4 and y–2x=5.
1 answer:
Answer:
5(x+1) -2(y-3) = 0
Step-by-step explanation:
For a given line ax+by=c and point (h, k), a perpendicular line through the point can be written as ...
b(x-h) -a(y-k) = 0
A graphing calculator shows the point of intersection of the graphs of the two lines to be (x, y) = (-1, 3), so the line perpendicular to 2x+5y=5 through that point can be written ...
5(x+1) -2(y-3) = 0
_____
In the attached graph, the requested line is shown in black.
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Answer:
A= 75.06 Sq Cm
Step-by-step explanation:
Please refer to the picture attached with this.
In ΔABD
AB = 8.5 , AD = 6 and say BD = x
Applying Pythagoras theorem in this triangle
Pythagoras theorem says
where c is the side opposite to the right angle, and b and a are the other two sides of the right angled triangle.
Hence side
a = 6.02+19
a = 25.02
Now we apply the formula for area of a triangle which is given as
Where b is the base , here we have base as a = 25.02
h is the height , here h = 6
Putting these values in Formula we get
Hence Area of the triangle is 75.06 sq cm
