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3 years ago

They intersect at the point (p, q). Which is greater, c or d? Explain how you know.

Mathematics

1 answer:

Natasha2012 [34]3 years ago

4 0

Answer:

d is greater than c, since at $x = 0, g(x) > f(x)$

Step-by-step explanation:

We are given two exponential functions, f and g.

Since f has the higher base(3 instead of 2 in g), it increases faster, so initially, g is greater than f, and after point (p,q), f is greater than g.

The values of c and d are found when $x = 0$ . At this point, we have that g is greater than f, so d is greater than c.

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Answer:

1.50b + 2.99p

Step-by-step explanation:

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Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation

just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation $v(t)= 6t^2-18t+12$ . We are asked to find the distance that the particle will travel in its first 2 seconds.

$s(t)=\int |v(t)|dt$

$s(t)=\int\limits^2_0 |6t^2-18t+12|dt$

Now, we will eliminate the absolute value sign as:

$s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt$

$s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1$

$s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1$

$s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))$

$s(2)=2-9+12-(0)-16+36-24-(-2+9-12)$

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$s(2)=5-4+5$

$s(2)=6$

Therefore, the particle will travel 6 feet in first 2 seconds.

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3 years ago

What is the value of 14(38−14)+33÷9?

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Step-by-step explanation:

14 of 24 + 33 ÷ 9

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3 years ago

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Dafna1 [17]

Answer:

I would believe that it is A.

Step-by-step explanation:

The fact that A has 5, and x is minus two times, 5/2= 2.5, and that is where the second arrowhead is pointing to on the x axis.

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3 years ago

2x-4y=20 what is the value of y

ra1l [238]

Answer: 20-2x/-4

Step-by-step explanation:

To actually solve for y as a number, you need two equations.

For this case move the 2x to the other side, making the equation -4y=20-2x.

Then divide by -4 on each side making the equation y=20-2x/-4.

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