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scoundrel [369]
4 years ago
13

How do you do this question?

Mathematics
1 answer:
LiRa [457]4 years ago
3 0

Step-by-step explanation:

arctan(x) is less than π/2 for x > 0.  Therefore, if we say g(x) = 13 (π/2) / eˣ, then f(x) < g(x) for all values of x > 0.

g(x) = 13 (π/2) / eˣ

g(x) = 13π/2 · (1/e)ˣ

So g(x) is a geometric series where r = 1/e.  Since |r| < 1, the series converges.

Since g(x) converges, the smaller f(x) also converges.

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Combine the like terms.<br> 7W-W+3
Bess [88]
The like terms are 7w and -w, so we can collect them to get:

6w+3

Hope this helps!! :)

7 0
3 years ago
Factor the expression using the GCF. The expression 21m−49n factored using the GCF is...
Roman55 [17]

Answer:  7(3m - 7n)

<u>Step-by-step explanation:</u>

Factor each term then see what value(s) they have in common:

          21m         -          49n

            ∧                        ∧

          3 · 7 · m              7 · 7 · n

Both terms have a 7 in common.  What is left over after removing the 7?

21m: 7(3m)

49n: 7(7n)

GCF: 7           Leftovers: 3m <em>and</em>  7n

Factored form of expression is: 7(3m - 7n)

6 0
3 years ago
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HELP! I WILL GIVE BRAINLIEST!
Nataliya [291]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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HELP PLEASE 21 POINTS PLEASE HELP ME!!!! &lt;3
Anna007 [38]

1)

n         1          2         3           4         5         6

f(n)    1033    932     831      730     629     528

First term (a₁):  <u>1033 </u>          Common difference (d): <u>-101 </u>

Explicit rule:  a_{n} = 1134 - 101n    Recursive rule: a_{n} = a_{n-1} - 101

a_{n} = a_{1} + d(n - 1)

a_{n} = 1033 - 101(n - 1)

a_{n} = 1033 - 101n + 101

a_{n} = 1134 - 101n

***********************************************************************************

2)

n         1          2         3           4         5         6

f(n)   -39      -29       -19        -9          9        19

First term (a₁):  <u> -39  </u>          Common difference (d): <u> +10  </u>

Explicit rule:  a_{n} = -49 + 10n    Recursive rule: a_{n} = a_{n-1} + 10

a_{n} = a_{1} + d(n - 1)

a_{n} = -39 + 10(n - 1)

a_{n} = -39 + 10n - 10

a_{n} = -49 + 10n

***********************************************************************************

3)

n         1          2         3           4         5         6

f(n)   3.75      2.5     1.25        0      -1.25     -2.5

First term (a₁):  <u> 3.75  </u>          Common difference (d): <u> -1.25  </u>

Explicit rule:  a_{n} = 5 - 1.25n    Recursive rule: a_{n} = a_{n-1} - 1.25

a_{n} = a_{1} + d(n - 1)

a_{n} = 3.75 - 1.25(n - 1)

a_{n} = 3.75 - 1.25n + 1.25

a_{n} = 5 - 1.25n


6 0
4 years ago
Eula needs to buy binders that cost $4 each and notebooks that cost $2 each. She has $20. The graph of the inequality 4x + 2y ≤
Zolol [24]
She has to buy both binders and notebooks. So, you have to take into account that she has to have both. The closest you can get to $20 while still getting notebooks, is to buy 4 binders. 4 times 4 equals 16. So, she can get 4 binders and 2 notebooks, because then, 2 times 2 equals 4 and 16 plus 4 equals 20.
8 0
3 years ago
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